PHP数组问题-未通过foreach循环

谢谢大家，问题回答了！如果有人感兴趣，更新后的函数如下，所有其他代码保持不变：

function fetch_questions($page) {
global $link;
$proc = mysqli_prepare($link, "SELECT * FROM tquestions_cwh WHERE page = ?");
mysqli_stmt_bind_param($proc, "i", $page);
mysqli_stmt_execute($proc);


$rowq = array();
stmt_bind_assoc($proc, $rowq);

// loop through all result rows
//  while ($proc->fetch()) {
    //  print_r($rowq);
//      $rows[]=$rowq;
//  }

while ($proc->fetch())
{
    foreach($rowq as $key=>$value )
    {
        $row_tmb[ $key ] = $value;
    } 
    $rows[] = $row_tmb; 
}

mysqli_stmt_close($proc);
mysqli_clean_connection($link);
return($rows);

}

嗯

代码如下：

function fetch_questions($page) {
    global $link;
    $proc = mysqli_prepare($link, "SELECT * FROM tquestions_cwh WHERE page = ?");
    mysqli_stmt_bind_param($proc, "i", $page);
    mysqli_stmt_execute($proc);


    $rows = array();
    stmt_bind_assoc($proc, $rowq);

    // loop through all result rows
    while ($proc->fetch()) {
        //  print_r($rowq);
        $rows[]=$rowq;
    }

    mysqli_stmt_close($proc);
    mysqli_clean_connection($link);
    return($rows);
}

然后我将其添加到php变量中，如下所示：

$qs = fetch_questions($page);

foreach($qs as $value){
                echo "<tr>".$value['qnum']." is the questions number and the question text is ".$value['qtext'].". The page and q values are ".$value['page']." and ".$value['questions']." respectively.</tr>";

然后我循环了一下，就像这样：

$qs = fetch_questions($page);

foreach($qs as $value){
                echo "<tr>".$value['qnum']." is the questions number and the question text is ".$value['qtext'].". The page and q values are ".$value['page']." and ".$value['questions']." respectively.</tr>";

这不是我想要的，出于信息目的，使用print函数的数组如下所示：

Array
    (
        [0] => Array
            (
                [questions] => q8
                [qnum] => 8
                [qtext] => I know how what I do fits into my team's objectives
                [page] => 1
            )

        [1] => Array
            (
                [questions] => q8
                [qnum] => 8
                [qtext] => I know how what I do fits into my team's objectives
                [page] => 1
            )

        [2] => Array
            (
                [questions] => q8
                [qnum] => 8
                [qtext] => I know how what I do fits into my team's objectives
                [page] => 1
            )

        [3] => Array
            (
                [questions] => q8
                [qnum] => 8
                [qtext] => I know how what I do fits into my team's objectives
                [page] => 1
            )

        [4] => Array
            (
                [questions] => q8
                [qnum] => 8
                [qtext] => I know how what I do fits into my team's objectives
                [page] => 1
            )

        [5] => Array
            (
                [questions] => q8
                [qnum] => 8
                [qtext] => I know how what I do fits into my team's objectives
                [page] => 1
            )

        [6] => Array
            (
                [questions] => q8
                [qnum] => 8
                [qtext] => I know how what I do fits into my team's objectives
                [page] => 1
            )

        [7] => Array
            (
                [questions] => q8
                [qnum] => 8
                [qtext] => I know how what I do fits into my team's objectives
                [page] => 1
            )

    )

很明显，它没有像应该的那样循环显示每一行……有什么建议吗

---

荷马。

对不起，我不太熟悉mysqli的程序风格，所以我不确定这是否是您的问题。然而，在我看来，您已经将$proc设置为mysqli_prepare的结果，但是，这个函数返回true或false。然后，您使用$proc作为mysqli_stmt_bind_param（）的第一个参数，但是，这个参数应该是mysqli_stmt_init（）的返回值，我假设它是$link。事实上，无论您在哪里使用$proc作为参数，都应该使用$link。

不确定是否还有更多，但标记是错误的：您缺少打开和关闭

。您发布的输出似乎已完成，它只显示在一行中。尝试：

foreach($qs as $value) {
    echo "<tr><td>".$value['qnum']." is the questions number and the question text is ".$value['qtext'].". The page and q values are ".$value['page']." and ".$value['questions']." respectively.</td></tr>";
}

foreach（$qs作为$value）{
回显“$value['qnum']”是问题编号，问题文本是“$value['qtext']”。页面和q值分别是“$value['page']”和“$value['questions']”；
}

mysqli\u stmt\u fetch手册上说：

注意：请注意，在调用mysqli_stmt_fetch（）之前，应用程序必须绑定所有列

对于

SELECT*

查询，您应该使用

mysqli\u stmt\u store\u result

和

mysqli\u stmt\u result\u metadata

函数来获取所有列。

我阅读了

/*
while ($proc->fetch()) {         
    //  print_r($rowq);         
    $rows[]=$rowq;         
}
*/
while ($proc->fetch())
{
    foreach($rowq as $key=>$value )
    {
        $row_tmb[ $key ] = $value;
    } 
    $row[] = $row_tmb; 
}

---

quote:问题在于返回的

$rowq

是引用而不是数据。因此，当您编写

$row[]=$rowq

时，

$row

将被数据集的最后一个元素填充。

数据库中的实际8个条目是什么？好奇的是，您能否使用：echo var_export（$qs，true）添加$qs数组的转储？请提供您的需要clearly@SpawnCxy-谢谢！我对你的代码做了一点小小的修改，阅读了上面编辑的问题。