Php 从Laravel中的验证程序发送自定义响应

我有一个注册用户路径，它采用

名称

，

电子邮件

和

密码

。如果数据正确，即存在唯一的电子邮件和参数，则它可以正常工作，但如果用户已注册，则Laravel会以自己的格式发送自动错误消息。我希望返回格式在成功或失败的情况下保持一致

成功注册返回数据：

{
    "status": "success",
    "token": "eyJ0eXAiOiJKV1QiLCJhbGciOiJIUzI1NiJ9.eyJzdWIiOjUsImlzcyI6Imh0dHA6Ly8xMjcuMC4wLjE6ODAwMC9hcGkvYXV0aC9yZWdpc3RlciIsImlhdCI6MTUyMTI3NTc5MiwiZXhwIjoxNTIxMjc5MzkyLCJuYmYiOjE1MjEyNzU3OTIsImp0aSI6Ik1wSzJSYmZYU1dobU5UR0gifQ.fdajaDooBTwP-GRlFmAu1gtC7_3U4ygD1TSBIqdPHf0"
}

但如果出现错误，它会以其他格式发送数据

{"message":"The given data was invalid.","errors":{"email":["The email has already been taken."]}}

我希望两者保持一致。成功返回数据很好。但如果发生故障，我想自定义数据。大概是这样的：

{"status":"error","message":"The given data was invalid.","errors":{"email":["The email has already been taken."]}}

基本上，我需要

status

param与每个响应一起出现

另外，在使用Postman时，我有一个查询，当出现错误时，输出是纯HTML。HTML页面是默认的Laravel页面。另一方面，当angular发送相同的请求时，错误是json格式，我刚刚粘贴在上面。 因为angular在任何情况下都会得到JSON响应，所以对我来说都很好。但为什么邮递员不给我看那个反应呢

寄存器控制器：

public function register(RegisterRequest $request)
    {
        $newUser = $this->user->create([
            'name' => $request->get('name'),
            'email' => $request->get('email'),
            'password' => bcrypt($request->get('password'))
        ]);
        if (!$newUser) {
            return response()->json(['status'=>'error','message'=>'failed_to_create_new_user'], 500);
        }

        return response()->json([
            'status' => 'success',
            'token' => $this->jwtauth->fromUser($newUser)
        ]);
    }

注册请求处理程序：

 public function authorize()
    {
        return true;
    }

    /**
     * Get the validation rules that apply to the request.
     *
     * @return array
     */
    public function rules()
    {
        return [
            'name' => 'required',
            'email' => 'required | email | unique:users,email',
            'password' => 'required'
        ];
    }

---

如果我理解正确，您总是在没有“状态”键的情况下得到错误响应

您当前的代码会发生以下几件事：

• RegisterController@register（RegisterRequest$请求）由路由调用
• Laravel看到您使用RegisterRequest类作为参数，并将为您实例化该类
• 实例化这个类意味着它将直接验证规则
• 如果不符合规则，laravel将直接响应发现的错误
• 此响应将始终位于laravel的默认“布局”中，代码在此停止

结论：当不满足验证规则时，甚至不会触发代码

我已经研究了一个解决方案，并得出了以下结论：

public function register(Illuminate\Http\Request $request)
{
    //Define your validation rules here.
    $rules = [
        'name' => 'required',
        'email' => 'required | email | unique:users,email',
        'password' => 'required'
    ];
    //Create a validator, unlike $this->validate(), this does not automatically redirect on failure, leaving the final control to you :)
    $validated = Illuminate\Support\Facades\Validator::make($request->all(), $rules);

    //Check if the validation failed, return your custom formatted code here.
    if($validated->fails())
    {
        return response()->json(['status' => 'error', 'messages' => 'The given data was invalid.', 'errors' => $validated->errors()]);
    }

    //If not failed, the code will reach here
    $newUser = $this->user->create([
        'name' => $request->get('name'),
        'email' => $request->get('email'),
        'password' => bcrypt($request->get('password'))
    ]);
    //This would be your own error response, not linked to validation
    if (!$newUser) {
        return response()->json(['status'=>'error','message'=>'failed_to_create_new_user'], 500);
    }

    //All went well
    return response()->json([
        'status' => 'success',
        'token' => $this->jwtauth->fromUser($newUser)
    ]);
}

现在，不符合验证规则仍然会触发错误，但您的错误，而不是laravel的内置错误：）

---

我希望有帮助

如果我理解正确，您总是在没有“状态”键的情况下得到错误响应

您当前的代码会发生以下几件事：

• RegisterController@register（RegisterRequest$请求）由路由调用
• Laravel看到您使用RegisterRequest类作为参数，并将为您实例化该类
• 实例化这个类意味着它将直接验证规则
• 如果不符合规则，laravel将直接响应发现的错误
• 此响应将始终位于laravel的默认“布局”中，代码在此停止

结论：当不满足验证规则时，甚至不会触发代码

我已经研究了一个解决方案，并得出了以下结论：

public function register(Illuminate\Http\Request $request)
{
    //Define your validation rules here.
    $rules = [
        'name' => 'required',
        'email' => 'required | email | unique:users,email',
        'password' => 'required'
    ];
    //Create a validator, unlike $this->validate(), this does not automatically redirect on failure, leaving the final control to you :)
    $validated = Illuminate\Support\Facades\Validator::make($request->all(), $rules);

    //Check if the validation failed, return your custom formatted code here.
    if($validated->fails())
    {
        return response()->json(['status' => 'error', 'messages' => 'The given data was invalid.', 'errors' => $validated->errors()]);
    }

    //If not failed, the code will reach here
    $newUser = $this->user->create([
        'name' => $request->get('name'),
        'email' => $request->get('email'),
        'password' => bcrypt($request->get('password'))
    ]);
    //This would be your own error response, not linked to validation
    if (!$newUser) {
        return response()->json(['status'=>'error','message'=>'failed_to_create_new_user'], 500);
    }

    //All went well
    return response()->json([
        'status' => 'success',
        'token' => $this->jwtauth->fromUser($newUser)
    ]);
}

现在，不符合验证规则仍然会触发错误，但您的错误，而不是laravel的内置错误：）

---

我希望有帮助

这就是我想到的：

function validate(array $rules)
{
    $validator = Validator::make(request()->all(), $rules);
    $errors = (new \Illuminate\Validation\ValidationException($validator))->errors();
    if ($validator->fails()) {
        throw new \Illuminate\Http\Exceptions\HttpResponseException(response()->json(
            [
                'status'     => false,
                'message'    => "Some fields are missing!",
                'error_code' => 1,
                'errors'     => $errors,
            ], \Illuminate\Http\JsonResponse::HTTP_UNPROCESSABLE_ENTITY));
    }
}

创建助手目录（

App\Helpers

）并将其添加到文件中。别忘了将其添加到composer.json中

"autoload": {
    "files": [
        "app/Helpers/system.php",
    ],
},

现在，您可以在控制器中调用

validate（）

，并获得所需的：

validate([
    'email'    => 'required|email',
    'password' => 'required|min:6|max:32',
    'remember' => 'nullable|boolean',
    'captcha'  => 'prod_required|hcaptcha',
]);

---

这就是我想到的：

function validate(array $rules)
{
    $validator = Validator::make(request()->all(), $rules);
    $errors = (new \Illuminate\Validation\ValidationException($validator))->errors();
    if ($validator->fails()) {
        throw new \Illuminate\Http\Exceptions\HttpResponseException(response()->json(
            [
                'status'     => false,
                'message'    => "Some fields are missing!",
                'error_code' => 1,
                'errors'     => $errors,
            ], \Illuminate\Http\JsonResponse::HTTP_UNPROCESSABLE_ENTITY));
    }
}

创建助手目录（

App\Helpers

）并将其添加到文件中。别忘了将其添加到composer.json中

"autoload": {
    "files": [
        "app/Helpers/system.php",
    ],
},

现在，您可以在控制器中调用

validate（）

，并获得所需的：

validate([
    'email'    => 'required|email',
    'password' => 'required|min:6|max:32',
    'remember' => 'nullable|boolean',
    'captcha'  => 'prod_required|hcaptcha',
]);

---

在Laravel 8中，我添加了带有“success”的自定义invalidJson:false:

在app/Exceptions/Handler.php中：

/**
 * Convert a validation exception into a JSON response.
 *
 * @param  \Illuminate\Http\Request  $request
 * @param  \Illuminate\Validation\ValidationException  $exception
 * @return \Illuminate\Http\JsonResponse
 */
protected function invalidJson($request, ValidationException $exception)
{
    return response()->json([
        'success' => false,
        'message' => $exception->getMessage(),
        'errors' => $exception->errors(),
    ], $exception->status);
}

---

在Laravel 8中，我添加了带有“success”的自定义invalidJson:false:

在app/Exceptions/Handler.php中：

/**
 * Convert a validation exception into a JSON response.
 *
 * @param  \Illuminate\Http\Request  $request
 * @param  \Illuminate\Validation\ValidationException  $exception
 * @return \Illuminate\Http\JsonResponse
 */
protected function invalidJson($request, ValidationException $exception)
{
    return response()->json([
        'success' => false,
        'message' => $exception->getMessage(),
        'errors' => $exception->errors(),
    ], $exception->status);
}