Php MySQLI的问题
我可能太累了,正在查看一个小错误,但这段代码不会将任何信息输入到我的数据库中Php MySQLI的问题,php,mysql,mysqli,Php,Mysql,Mysqli,我可能太累了,正在查看一个小错误,但这段代码不会将任何信息输入到我的数据库中 $sql = "INSERT INTO TABLE_NAME (UPC, Description, Make, Model, SNLocation, IMEI_MEID, Resetting, Notes, Image) VALUES ($UPC, $Desc, $Make, $Model, $SNLocation, $IMEI_MEID, $Resetting, $Notes, $Image)"; mysqli_
$sql = "INSERT INTO TABLE_NAME (UPC, Description, Make, Model, SNLocation, IMEI_MEID, Resetting, Notes, Image)
VALUES ($UPC, $Desc, $Make, $Model, $SNLocation, $IMEI_MEID, $Resetting, $Notes, $Image)";
mysqli_query($con, $sql) or die(mysqli_error($sql));
有人能帮我检查一下这是否有语法问题或其他问题吗?这是因为您有一个错误
$sql = "INSERT INTO TABLE_NAME (UPC, Description, Make, Model, SNLocation, IMEI_MEID, Resetting, Notes, Image)
VALUES ('$UPC', '$Desc', '$Make', '$Model', '$SNLocation', '$IMEI_MEID', '$Resetting', '$Notes', '$Image')";
已删除]从
注释,图像)]
您需要删除]
并用单引号括起字符串值('
):
$sql=“插入表\u名称
(UPC、说明、品牌、型号、,
SNLocation、IMEI\U MEID、重置、注释、图像)]
值($UPC、$Desc、$Make、$Model、$SNLocation、$IMEI_MEID、$RESETING、$Notes、$Image)”;
mysqli_查询($con,$sql)或die(mysqli_错误($sql));
(仅供参考:如果答案确实对您有帮助,您可以接受或投票)
$sql = "INSERT INTO TABLE_NAME
(UPC, Description, Make, Model,
SNLocation, IMEI_MEID, Resetting, Notes, Image)] <-- Here -->
VALUES ($UPC, $Desc, $Make, $Model, $SNLocation, $IMEI_MEID, $Resetting, $Notes, $Image)";
mysqli_query($con, $sql) or die(mysqli_error($sql));