PHP-使用特定索引/键将数组转换为json

我收到一个数组，希望通过在PHP中使用带有特定索引/键的json_encode将其转换为json。数组结果：

{"StatusCode": "2800",
 "card": {
 "studentcard": {
 "1000": [
{
 "Name": "Jerome",
 "CardNumber": "512314512312",
 "CardExpiry": "2017-03-24",
 "CardType": "Library",
},
{
 "Name": "Jerome",
 "CardNumber": "512314512312-b",
 "CardExpiry": "2017-10-22",
 "CardType": "IT",
}],
"1001": [
{
 "Name": "Jason",
 "CardNumber": "512314512313",
 "CardExpiry": "2017-10-22",
 "CardType": "Library",
}]
}

JSON中的预期结果

[
 {
  "Name": "Jerome",
  "CardNumber": "512314512312",
  "CardExpiry": "2017-03-24",
  "CardType": "Library"
 },
 {
  "Name": "Jerome",
  "CardNumber": "512314512312-b",
  "CardExpiry": "2017-10-22",
  "CardType": "IT"
 },
 {
  "Name": "Jason",
  "CardNumber": "512314512313",
  "CardExpiry": "2017-10-22",
  "CardType": "Library"
 }
]

---

如何删除StatusCode、card、studentcard、1000并将其编码为JSON中的预期结果？

使用

JSON\u decode

和

array\u merge

函数的有效JSON字符串解决方案：

$json_str = '{
    "StatusCode": "2800",
    "card": {
        "studentcard": {
            "1000": [{
                "Name": "Jerome",
                "CardNumber": "512314512312",
                "CardExpiry": "2017-03-24",
                "CardType": "Library"
            }, {
                "Name": "Jerome",
                "CardNumber": "512314512312-b",
                "CardExpiry": "2017-10-22",
                "CardType": "IT"
            }],
            "1001": [{
                "Name": "Jason",
                "CardNumber": "512314512313",
                "CardExpiry": "2017-10-22",
                "CardType": "Library"
            }]
        }
    }
}';

$data = json_decode($json_str, true);
$data = array_merge($data["card"]["studentcard"]["1000"], $data["card"]["studentcard"]["1001"]);
$json = json_encode($data, JSON_PRETTY_PRINT);

echo $json;

输出：

[
    {
        "Name": "Jerome",
        "CardNumber": "512314512312",
        "CardExpiry": "2017-03-24",
        "CardType": "Library"
    },
    {
        "Name": "Jerome",
        "CardNumber": "512314512312-b",
        "CardExpiry": "2017-10-22",
        "CardType": "IT"
    },
    {
        "Name": "Jason",
        "CardNumber": "512314512313",
        "CardExpiry": "2017-10-22",
        "CardType": "Library"
    }
]

---

您可以使用

调用用户函数数组（'array\u merge'，…）展平该数组。

：

看到它在或上运行

---

请注意，在JSON中，对象的最后一个属性后面不能有逗号（即右大括号之前）。此外，您还缺少两个右大括号。

初始json无效这只是一个猜测，但他可能需要一个解决方案，该解决方案不需要硬编码

1000

和

1001

，并且可以处理

学生卡中的两个以上元素。您的解决方案非常有效。别想了。感谢对json格式的更正。编辑
$obj = json_decode($json, true);
$result = call_user_func_array('array_merge', $obj["card"]["studentcard"]);
$json = json_encode($result, JSON_PRETTY_PRINT);