Php 找到Magento 404页，未调用块

我已经在控制器中创建了一个带有2个函数的自定义模块，一个用于索引页面，另一个用于成功页面。我可以访问索引页面，但当我在url中进入成功页面时，它会显示404Found。我不知道我在哪里犯了错误

我的模块名为instagram..我的控制器代码：

   app/code/local/Blazedream/Instagram/controllers/IndexController.php
   <?php

  class Blazedream_Instagram_IndexController extends Mage_Core_Controller_Front_Action
  {
 public function indexAction() {

    $this->loadLayout();
    $this->getLayout()->getBlock('login.instagram');

    //print_r($this->getLayout()->getBlock('footer.topvendors'));die;

    $this->renderLayout();


}
public function successAction() {
    echo "hello hello"; die;
    $this->loadLayout();
    $this->getLayout()->getBlock('login.success');

    //print_r($this->getLayout()->getBlock('footer.topvendors'));die;

    $this->renderLayout();


}
}

访问控制器中成功功能的我的url:

       http://192.168.1.188/projects/shopu_v2/trunk/shopu/index.php/instagram

     http://192.168.1.188/projects/shopu_v2/trunk/shopu/index.php/instagram/success

谁能帮我指点一下我犯了什么错误。

---

提前感谢。

请告诉我您成功使用的完整url。请稍候，我将编辑url。您输入了错误的url，请尝试此

http://192.168.1.188/projects/shopu_v2/trunk/shopu/index.php/instagram/index/success

相同的404只有comingSimBeez是对的。请检查两次。你的url应该是index.php/frontname/controller/action，在你的例子中是index.php/instagram/index/successPlease告诉我你成功使用的完整url。等等，我将编辑url。你输入了错误的url，请尝试此

http://192.168.1.188/projects/shopu_v2/trunk/shopu/index.php/instagram/index/success

相同的404只有comingSimBeez是对的。请检查两次。您的url应该类似于index.php/frontname/controller/action，在您的示例中是index.php/instagram/index/success

         app/code/local/Blazedream/Instagram/Block/Loginblock/Success.php
        <?php
   class Blazedream_Instagram_Block_Loginblock_Success extends Mage_Core_Block_Template {

public function successblock() {
    $success = "success";
    return $success;    

}
}

   app/design/frontend/mtquartz03/default/layout/instagram.xml
   <?xml version="1.0"?>
     <layout version="0.1.0">
    <default>
      <reference name="content">
      </reference>
  </default>
  <instagram_index_index>  
       <reference name="content">
             <block type="instagram/loginblock" name="login.instagram" template="instagramlogin/instagram.phtml"></block>
       </reference>
  </instagram_index_index>
  <instagram_index_success>  
       <reference name="content">
             <block type="instagram/loginblock_success" name="login.success" template="instagramlogin/success.phtml"></block>
       </reference>
  </instagram_index_success>
  </layout>

       http://192.168.1.188/projects/shopu_v2/trunk/shopu/index.php/instagram

     http://192.168.1.188/projects/shopu_v2/trunk/shopu/index.php/instagram/success