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如何在PHPUnit模拟对象中测试第二个参数_Php_Phpunit - Fatal编程技术网

如何在PHPUnit模拟对象中测试第二个参数

如何在PHPUnit模拟对象中测试第二个参数,php,phpunit,Php,Phpunit,这就是我所拥有的: $observer = $this->getMock('SomeObserverClass', array('method')); $observer->expects($this->once()) ->method('method') ->with($this->equalTo($arg1)); 但该方法应采用两个参数。我只是测试第一个参数是否正确传递(如$arg1) 如何测试第二个参数?我认为这样做

这就是我所拥有的:

$observer = $this->getMock('SomeObserverClass', array('method'));
$observer->expects($this->once())
         ->method('method')
         ->with($this->equalTo($arg1));
但该方法应采用两个参数。我只是测试第一个参数是否正确传递(如$arg1)


如何测试第二个参数?

我认为这样做的方法是:

$observer->expects($this->once())
     ->method('method')
     ->with($this->equalTo($arg1),$this->equalTo($arg2));

如果需要在第二个参数上执行不同类型的断言,也可以这样做:

$observer->expects($this->once())
     ->method('method')
     ->with($this->equalTo($arg1),$this->stringContains('some_string'));
如果需要确保某个参数传递多个断言,请使用logicalAnd()


几周前我遇到了这个。使用:->with($this->equalTo($foo,$bar)对我来说很有效。@请确保equalTo()的第二个参数是$delta,所以这可能与您认为的不一样。
$observer->expects($this->once())
     ->method('method')
     ->with($this->equalTo($arg1),$this->stringContains('some_string'));
$observer->expects($this->once())
     ->method('method')
     ->with($this->logicalAnd($this->stringContains('a'), $this->stringContains('b')));