php为sql全文搜索准备的语句

大家好，我这里需要帮助，我正在尝试使用PHP prepare语句进行SQL全文搜索这是我尝试过的

//sql 1: $sql = "SELECT title FROM business WHERE MATCH (title,description) AGAINST ('?')";
//sql 2: $sql = "SELECT title FROM business WHERE MATCH (title,description) AGAINST (:string)";
//bind 1: $stmt->bind_param("s", $q);
//bind 2: $stmt->bind_param(":string", $q)'

$q = $_POST['name'];
$stmt = $mysqli->prepare($sql);
$stmt->bind_param("s", $q);//tried both binds
$stmt->execute();
$stmt->bind_result($title);
while ($stmt->fetch()){
    @$result .= '<a href="'.$title.'" target="_blank"> <div class="dproped container">'.$title.'</div> </a>';
}
$stmt->close();
echo json_encode(array('searchresult' => $result));

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那么您想在php中搜索文本文件吗？

sql 1

不正确，您没有引用占位符。我不认为

mysqli

会与

mssql

一起工作。你在使用

mssql

还是

mysql

？@Ben正在搜索database@chris85我不知道Bind 2有语法错误<代码>$stmt->bind_参数（“：string”，$q）”用引号代替分号<代码>sql 1您引用了占位符，因此它是一个文本

？

，而不是占位符

$sql=“从业务中选择与（？）匹配（标题、说明）的标题”。
$db_host = "localhost"; //Host address 
$db_name = "1111"; //Name of Database
$db_user = "111"; //Name of database user
$db_pass = "111"; //Password for database user
$mysqli = new mysqli($db_host, $db_user, $db_pass, $db_name);