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Php 使用带有ajax和formdata的codeigniter上传图像_Php_Jquery_Ajax_Codeigniter_File Upload - Fatal编程技术网

Php 使用带有ajax和formdata的codeigniter上传图像

Php 使用带有ajax和formdata的codeigniter上传图像,php,jquery,ajax,codeigniter,file-upload,Php,Jquery,Ajax,Codeigniter,File Upload,我喜欢使用PHP中的codeigniter框架和jQueryAjax上传图像,而无需重定向页面。当我上传图像时,它会重定向到控制器区域,并且值不会插入到数据库中,ajax响应也不会出现 谁能解决我的问题。。。。先谢谢你 这是我的查看区域。 <form action="<?php echo site_url("Admin_Creator/do_upload")?>" enctype="multipart/form-data" accept-charset="utf-8" nam

我喜欢使用PHP中的codeigniter框架和jQueryAjax上传图像,而无需重定向页面。当我上传图像时,它会重定向到控制器区域,并且值不会插入到数据库中,ajax响应也不会出现

谁能解决我的问题。。。。先谢谢你

这是我的查看区域。

<form  action="<?php echo site_url("Admin_Creator/do_upload")?>" enctype="multipart/form-data" accept-charset="utf-8" name="formname" id="frm_imageuupload"  method="post">
               <div class="form-group">
               <label for="menu">Select Menu</label>
                   <select class="form-control" id="selectmenuid">
                    <option value="">-- Select Menu --</option>
                    <?php foreach($showData as $show):?>
                      <option value="<?php echo $show->menu_id?>"><?php echo $show->menu_name?></option>
                    <?php endforeach;?>
                    </select>
                </div>
               <div class="form-group">
               <label for="menu">Select Sub Menu</label>
                   <select class="form-control" id="selectsubmenu">
                       <option>--Select Sub Menu--</option>
                    </select>
               </div>
              <div class="form-group">
                  <label for="imagetitle">Image Title</label>
                  <input type="text" class="form-control" name="imagetitle" id="imagetitle" placeholder="Enter Image Title" required="required">
                </div>
               <div class="control-group form-group">
                        <div class="controls">
                            <label>Upload Photo:</label>
                            <input name="file" type="file" id="image_file" required>
                            <p class="help-block"></p>
                        </div>
               </div>
               <button type="submit" class="btn btn-primary" id="submit">Submit</button>
           </form>
 public function do_upload(){
        $config['upload_path']="./upload";
        $config['allowed_types']='gif|jpg|png';
        $this->load->library('upload',$config);
        if($this->upload->do_upload()){
        $data = array('upload_data' => $this->upload->data());
        $data1 = array(
        'menu_id' => $this->input->post('selectmenuid'),
        'submenu_id' => $this->input->post('selectsubmenu'),
        'imagetitle' => $this->input->post('imagetitle'),
        'imgpath' => $data['upload_data']['file_name']
        );  
        $result= $this->Admin_model->save_imagepath($data1);
        if ($result == TRUE) {
            echo "true";
        }
        }

     }
这是我的型号编码

$('#submit').on('click',function(){
        var inputFile=$('input[name=file]');
        var fileToUpload=inputFile[0].files[0];
        var other_data = $('#frm_imageuupload').serializeArray();
        var formdata=new FormData();
        formdata.append(fileToUpload);
        formdata.append(other_data);
         //now upload the file using ajax
         $.ajax({
             url:"<?php echo base_url('Admin_Creator/do_upload') ?>",
             type:"post",
             data:formdata,
             processData:false,
             contentType:false,
              success: function(data){
            if (data== 'true'){   
               window.location.reload();
            }
            else{
               alert("Pls Try Again");
            }
           }
         });
public function save_imagepath($data1)
    {
        $this->db->insert('images', $data1);
         return $this->db->insert_id();
    }
这很简单。
问题在于ajax
您应该先停止表单提交

$('form').on('submit',function(e){//bind event on form submit.
   e.preventDefault();//stop submit
   .........          //your other codes
这很简单。
问题在于ajax
您应该先停止表单提交

$('form').on('submit',function(e){//bind event on form submit.
   e.preventDefault();//stop submit
   .........          //your other codes

试试这个。它正在工作-
HTML表单-

<form enctype="multipart/form-data" id="submit">
               <div class="form-group">
               <label for="menu">Select Menu</label>
                   <select class="form-control" name="selectmenuid" id="selectmenuid">
                    <option value="">-- Select Menu --</option>
                    <?php foreach($showData as $show):?>
                      <option value="<?php echo $show->menu_id?>"><?php echo $show->menu_name?></option>
                    <?php endforeach;?>
                    </select>
                </div>
               <div class="form-group">
               <label for="menu">Select Sub Menu</label>
                   <select class="form-control" name="selectsubmenu" id="selectsubmenu">
                       <option>--Select Sub Menu--</option>
                    </select>
               </div>
              <div class="form-group">
                  <label for="imagetitle">Image Title</label>
                  <input type="text" class="form-control" name="imagetitle" id="imagetitle" placeholder="Enter Image Title" required="required">
                </div>
               <div class="control-group form-group">
                        <div class="controls">
                            <label>Upload Photo:</label>
                            <input name="file" type="file"  id="image_file" required>
                            <p class="help-block"></p>
                        </div>
               </div>
               <button type="submit" class="btn btn-primary" id="sub">Submit</button>
           </form>  
$('#submit').submit(function(e){
    e.preventDefault(); 
         $.ajax({
             url:'Your path',
             type:"post",
             data:new FormData(this),
             processData:false,
             contentType:false,
             cache:false,
             async:false,
              success: function(data){
                  alert(data);
           }
         });
    });  
public function do_upload(){
        $config['upload_path']="./upload";
        $config['allowed_types']='gif|jpg|png';
        $this->load->library('upload',$config);
        if($this->upload->do_upload("file")){
        $data = array('upload_data' => $this->upload->data());
        $data1 = array(
        'menu_id' => $this->input->post('selectmenuid'),
        'submenu_id' => $this->input->post('selectsubmenu'),
        'imagetitle' => $this->input->post('imagetitle'),
        'imgpath' => $data['upload_data']['file_name']
        );  
        $result= $this->Admin_model->save_imagepath($data1);
        if ($result == TRUE) {
            echo "true";
        }
        }

     }
只需在ajax中设置url,它就能完美工作。
控制器功能-

<form enctype="multipart/form-data" id="submit">
               <div class="form-group">
               <label for="menu">Select Menu</label>
                   <select class="form-control" name="selectmenuid" id="selectmenuid">
                    <option value="">-- Select Menu --</option>
                    <?php foreach($showData as $show):?>
                      <option value="<?php echo $show->menu_id?>"><?php echo $show->menu_name?></option>
                    <?php endforeach;?>
                    </select>
                </div>
               <div class="form-group">
               <label for="menu">Select Sub Menu</label>
                   <select class="form-control" name="selectsubmenu" id="selectsubmenu">
                       <option>--Select Sub Menu--</option>
                    </select>
               </div>
              <div class="form-group">
                  <label for="imagetitle">Image Title</label>
                  <input type="text" class="form-control" name="imagetitle" id="imagetitle" placeholder="Enter Image Title" required="required">
                </div>
               <div class="control-group form-group">
                        <div class="controls">
                            <label>Upload Photo:</label>
                            <input name="file" type="file"  id="image_file" required>
                            <p class="help-block"></p>
                        </div>
               </div>
               <button type="submit" class="btn btn-primary" id="sub">Submit</button>
           </form>  
$('#submit').submit(function(e){
    e.preventDefault(); 
         $.ajax({
             url:'Your path',
             type:"post",
             data:new FormData(this),
             processData:false,
             contentType:false,
             cache:false,
             async:false,
              success: function(data){
                  alert(data);
           }
         });
    });  
public function do_upload(){
        $config['upload_path']="./upload";
        $config['allowed_types']='gif|jpg|png';
        $this->load->library('upload',$config);
        if($this->upload->do_upload("file")){
        $data = array('upload_data' => $this->upload->data());
        $data1 = array(
        'menu_id' => $this->input->post('selectmenuid'),
        'submenu_id' => $this->input->post('selectsubmenu'),
        'imagetitle' => $this->input->post('imagetitle'),
        'imgpath' => $data['upload_data']['file_name']
        );  
        $result= $this->Admin_model->save_imagepath($data1);
        if ($result == TRUE) {
            echo "true";
        }
        }

     }

试试这个。它正在工作-
HTML表单-

<form enctype="multipart/form-data" id="submit">
               <div class="form-group">
               <label for="menu">Select Menu</label>
                   <select class="form-control" name="selectmenuid" id="selectmenuid">
                    <option value="">-- Select Menu --</option>
                    <?php foreach($showData as $show):?>
                      <option value="<?php echo $show->menu_id?>"><?php echo $show->menu_name?></option>
                    <?php endforeach;?>
                    </select>
                </div>
               <div class="form-group">
               <label for="menu">Select Sub Menu</label>
                   <select class="form-control" name="selectsubmenu" id="selectsubmenu">
                       <option>--Select Sub Menu--</option>
                    </select>
               </div>
              <div class="form-group">
                  <label for="imagetitle">Image Title</label>
                  <input type="text" class="form-control" name="imagetitle" id="imagetitle" placeholder="Enter Image Title" required="required">
                </div>
               <div class="control-group form-group">
                        <div class="controls">
                            <label>Upload Photo:</label>
                            <input name="file" type="file"  id="image_file" required>
                            <p class="help-block"></p>
                        </div>
               </div>
               <button type="submit" class="btn btn-primary" id="sub">Submit</button>
           </form>  
$('#submit').submit(function(e){
    e.preventDefault(); 
         $.ajax({
             url:'Your path',
             type:"post",
             data:new FormData(this),
             processData:false,
             contentType:false,
             cache:false,
             async:false,
              success: function(data){
                  alert(data);
           }
         });
    });  
public function do_upload(){
        $config['upload_path']="./upload";
        $config['allowed_types']='gif|jpg|png';
        $this->load->library('upload',$config);
        if($this->upload->do_upload("file")){
        $data = array('upload_data' => $this->upload->data());
        $data1 = array(
        'menu_id' => $this->input->post('selectmenuid'),
        'submenu_id' => $this->input->post('selectsubmenu'),
        'imagetitle' => $this->input->post('imagetitle'),
        'imgpath' => $data['upload_data']['file_name']
        );  
        $result= $this->Admin_model->save_imagepath($data1);
        if ($result == TRUE) {
            echo "true";
        }
        }

     }
只需在ajax中设置url,它就能完美工作。
控制器功能-

<form enctype="multipart/form-data" id="submit">
               <div class="form-group">
               <label for="menu">Select Menu</label>
                   <select class="form-control" name="selectmenuid" id="selectmenuid">
                    <option value="">-- Select Menu --</option>
                    <?php foreach($showData as $show):?>
                      <option value="<?php echo $show->menu_id?>"><?php echo $show->menu_name?></option>
                    <?php endforeach;?>
                    </select>
                </div>
               <div class="form-group">
               <label for="menu">Select Sub Menu</label>
                   <select class="form-control" name="selectsubmenu" id="selectsubmenu">
                       <option>--Select Sub Menu--</option>
                    </select>
               </div>
              <div class="form-group">
                  <label for="imagetitle">Image Title</label>
                  <input type="text" class="form-control" name="imagetitle" id="imagetitle" placeholder="Enter Image Title" required="required">
                </div>
               <div class="control-group form-group">
                        <div class="controls">
                            <label>Upload Photo:</label>
                            <input name="file" type="file"  id="image_file" required>
                            <p class="help-block"></p>
                        </div>
               </div>
               <button type="submit" class="btn btn-primary" id="sub">Submit</button>
           </form>  
$('#submit').submit(function(e){
    e.preventDefault(); 
         $.ajax({
             url:'Your path',
             type:"post",
             data:new FormData(this),
             processData:false,
             contentType:false,
             cache:false,
             async:false,
              success: function(data){
                  alert(data);
           }
         });
    });  
public function do_upload(){
        $config['upload_path']="./upload";
        $config['allowed_types']='gif|jpg|png';
        $this->load->library('upload',$config);
        if($this->upload->do_upload("file")){
        $data = array('upload_data' => $this->upload->data());
        $data1 = array(
        'menu_id' => $this->input->post('selectmenuid'),
        'submenu_id' => $this->input->post('selectsubmenu'),
        'imagetitle' => $this->input->post('imagetitle'),
        'imgpath' => $data['upload_data']['file_name']
        );  
        $result= $this->Admin_model->save_imagepath($data1);
        if ($result == TRUE) {
            echo "true";
        }
        }

     }

这就是我为解决那个问题所做的

HTML

模型

     class profile_sp_m extends CI_Model
     {
        public $_tablename = 'profiles';

        function __construct()
        {
          // Call the Model constructor
          parent::__construct();
        }

        public function upload_logo($data) {

            $caption = $data['caption'];
            $details = $data['details'];

            if(isset($_FILES["file"]["type"]))
            {
              $validextensions = array("jpeg", "jpg", "png");
              $temporary = explode(".", $_FILES["file"]["name"]);
              $file_extension = end($temporary);

              if ((($_FILES["file"]["type"] == "image/png") ||($_FILES["file"]["type"] == "image/jpg") || 
                 ($_FILES["file"]["type"] == "image/jpeg") ) && 
                 ($_FILES["file"]["size"] < 100000) && 
                  in_array($file_extension, $validextensions)){
                 if ($_FILES["file"]["error"] > 0)
                  {
                      echo "Return Code: " . $_FILES["file"]["error"] . "<br/><br/>";
                  } else {
                    $sourcePath = $_FILES['file']['tmp_name']; Store source path in a variable
                    $targetPath = "uploads/profiles/" . $_FILES['file']['name']; // The Target path where file is to be stored
                    move_uploaded_file($sourcePath,$targetPath); // Moving Uploaded file
                     // The Image Data
                     $imageData = [
                         'caption'   => $caption,
                         'description'   => $details,
                     ];

                     // Insert the data
                     $this->db->insert($this->_tablename, $imageData);
                  }
              }
           }

        }



     }
class profile\u sp\m扩展了CI\u模型
{
public$_tablename='profiles';
函数_u构造()
{
//调用模型构造函数
父项::_构造();
}
公共功能上传标志($data){
$caption=$data['caption'];
$details=$data['details'];
如果(isset($\u文件[“文件”][“类型”]))
{
$validextensions=数组(“jpeg”、“jpg”、“png”);
$temporary=explode(“.”,$_文件[“文件”][“名称”]);
$file_extension=end($temporary);
如果(($_文件[“文件”][“类型”]=“图像/png”)||($_文件[“文件”][“类型”]=“图像/jpg”)||
($_文件[“文件”][“类型”]=“图像/jpeg”)&&
($_文件[“文件”][“大小”]<100000)和
在数组中($file_扩展名,$validex)){
如果($\u文件[“文件”][“错误”]>0)
{
回显“返回代码:”.$\u文件[“文件”][“错误”]。“

”; }否则{ $sourcePath=$\u FILES['file']['tmp\u name'];将源路径存储在变量中 $targetPath=“uploads/profiles/”$\u FILES['file']['name'];//存储文件的目标路径 移动上传的文件($sourcePath,$targetPath);//移动上传的文件 //图像数据 $imageData=[ 'caption'=>$caption, 'description'=>$details, ]; //插入数据 $this->db->insert($this->\u tablename,$imageData); } } } } }
这就是我为解决那个问题所做的

HTML

模型

     class profile_sp_m extends CI_Model
     {
        public $_tablename = 'profiles';

        function __construct()
        {
          // Call the Model constructor
          parent::__construct();
        }

        public function upload_logo($data) {

            $caption = $data['caption'];
            $details = $data['details'];

            if(isset($_FILES["file"]["type"]))
            {
              $validextensions = array("jpeg", "jpg", "png");
              $temporary = explode(".", $_FILES["file"]["name"]);
              $file_extension = end($temporary);

              if ((($_FILES["file"]["type"] == "image/png") ||($_FILES["file"]["type"] == "image/jpg") || 
                 ($_FILES["file"]["type"] == "image/jpeg") ) && 
                 ($_FILES["file"]["size"] < 100000) && 
                  in_array($file_extension, $validextensions)){
                 if ($_FILES["file"]["error"] > 0)
                  {
                      echo "Return Code: " . $_FILES["file"]["error"] . "<br/><br/>";
                  } else {
                    $sourcePath = $_FILES['file']['tmp_name']; Store source path in a variable
                    $targetPath = "uploads/profiles/" . $_FILES['file']['name']; // The Target path where file is to be stored
                    move_uploaded_file($sourcePath,$targetPath); // Moving Uploaded file
                     // The Image Data
                     $imageData = [
                         'caption'   => $caption,
                         'description'   => $details,
                     ];

                     // Insert the data
                     $this->db->insert($this->_tablename, $imageData);
                  }
              }
           }

        }



     }
class profile\u sp\m扩展了CI\u模型
{
public$_tablename='profiles';
函数_u构造()
{
//调用模型构造函数
父项::_构造();
}
公共功能上传标志($data){
$caption=$data['caption'];
$details=$data['details'];
如果(isset($\u文件[“文件”][“类型”]))
{
$validextensions=数组(“jpeg”、“jpg”、“png”);
$temporary=explode(“.”,$_文件[“文件”][“名称”]);
$file_extension=end($temporary);
如果(($_文件[“文件”][“类型”]=“图像/png”)||($_文件[“文件”][“类型”]=“图像/jpg”)||
($_文件[“文件”][“类型”]=“图像/jpeg”)&&
($_文件[“文件”][“大小”]<100000)和
在数组中($file_扩展名,$validex)){
如果($\u文件[“文件”][“错误”]>0)
{
回显“返回代码:”.$\u文件[“文件”][“错误”]。“

”; }否则{ $sourcePath=$\u FILES['file']['tmp\u name'];将源路径存储在变量中 $targetPath=“uploads/profiles/”$\u FILES['file']['name'];//存储文件的目标路径 移动上传的文件($sourcePath,$targetPath);//移动上传的文件 //图像数据 $imageData=[ 'caption'=>$caption, 'description'=>$details, ]; //插入数据 $this->db->insert($this->\u tablename,$imageData); } } } } }
首先将js代码更改为这两行。。它将要求ajaxi这样做之后,我得到了同样的问题。。。在控制台中,it错误显示为“未能在“FormData”上执行“append”:需要2个参数,但只存在1个参数。”感谢您的回答。请先将js代码更改为这2行。。它将要求ajaxi这样做之后,我得到了同样的问题。。。在控制台中,it错误显示为“未能在“FormData”上执行“append”:需要2个参数,但只有1个参数。谢谢您的回答。谢谢。。但我想按照html表单将此路径添加到数据库中。。我检查了一下,主线程上console.log-SynchronousXMLHttpRequest中显示的错误已被弃用,因为它会对最终用户的体验产生有害影响。如需更多帮助,请查看。发送@jquery.min.js:4 2http://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js ,加载资源失败:服务器响应状态为500(内部服务器错误),请删除此“async:false”@AntoAlexanderthank。。但我想按照html表单将此路径添加到数据库中。。我检查了一下,主线程上console.log-SynchronousXMLHttpRequest中显示的错误是d