Php 将sql语句转换为laravel'；s DB:raw

我想在我的laravel/mysql后端的一个半径内找到场地，我有一个sql语句，我想这会对我有所帮助，但我需要将它转换成一些有说服力的东西，我可以理解，我可以这样做

Venue::select(DB:raw( /SENTENCE GOES HERE/)

但我不知道如何将sql语法转换为正确格式的字符串，以下是我的代码：

        $latitude = $request->input('lat') ?? 36.720240;
        $longitude = $request->input('lng') ?? -4.405770;
        
        $point = point($latitude, $longitude);
        $radius = 0.1;
        $polygon = ST_Buffer($point, $radius);

        $venues = [];

        //How to transform this thing right here into DB::raw or something laravel can understand
        select v.name, st_distance_sphere(point(v.lat, v.lng), point($lat, $lng)) as dist
        from venues v
        where st_within(point(v.lat, v.lng), $polygon)
        order by dist
        limit 50