Php 狂饮；使用基本URL、标题和POST设置客户端

我在纠正语法方面遇到了困难，我将非常感谢您的帮助；我正在尝试设置包含基本URL和一些必要的头信息（包括自定义安全令牌）的客户端

下一步是发布到Web服务：

$baseServiceURL = ['base_uri' => 'http://127.0.0.1:8080/service/v1/ws//something/update']; 
$theHeaders = ['Content-Type' => 'application/json', 'Accept' =>  'application/json', 'token' => 'test-token'];

$updateRequestClient = new Client($baseServiceURL, array(
    "request.options" => array(
       "headers" => $theHeaders
    )
));

//var 1 coming from elsewhere
$varNum2 = $q;
$varNum3 = $w;
$varNum4 = $e;
$varNum5 = $r;
$varNum6 = $t;
$varNum7 = 'me';

// json name/value pairs
$updateBody['name1'] = $varNum1;
$updateBody['name2'] = $varNum2;
$updateBody['name3'] = $varNum3;
$updateBody['name4'] = $varNum4;
$updateBody['name5'] = $varNum5;
$updateBody['name6'] = $varNum6;
$updateBody['name7'] = $varNum7;

//send
$updateRequestResponse = $updateRequestClient->post([ 'body' => json_encode($updateBody) ]);

//response 200??
$responseCode = $updateRequestResponse->getStatusCode();

if ($responseCode == "200") {                                                  

echo ("SUCCESS");

}

我的HTML端出现以下错误：

警告：parse_url（）希望参数1是字符串，数组在第51行的C:\xampp\vendor\guzzlehttp\psr7\src\Uri.php中给出

可捕获的致命错误：传递给GuzzleHttp\Psr7\Uri:：applyParts（）的参数1必须是数组类型，给定为null，在第55行的C:\xampp\vendor\GuzzleHttp\Psr7\src\Uri.php中调用，在第410行的C:\xampp\vendor\GuzzleHttp\Psr7\src\Uri.php中定义

如果我将URL更改为string

$baseServiceURL=（string）（'http://127.0.0.1:8080/service/v1/ws//something/update');我得到：

可捕获致命错误：参数1传递给
GuzzleHttp\Client:：_construct（）必须是数组字符串类型
给定，在C:\xampp\htdocs\SSQueryTool\updateDoctor.php中在线调用
79，并在上的C:\xampp\vendor\guzzlehttp\guzzle\src\Client.php中定义
第62行

客户端只接受构造函数中的一个参数
经过一整天的工作，我终于让它工作了，请在下面找到我的详细信息：

//PREP PAYLOAD (varNum1 coming from elsewhere)
$varNum2 = $q;
$varNum3 = $w;
$varNum4 = $e;
$varNum5 = $r;
$varNum6 = $t;
$varNum7 = 'me';

//THE WEBSERVICE UPDATE BASE URL 
$baseServiceURL = (string)('http://127.0.0.1:8080/service/v1/ws//something/update'); 

$updateRequestClient = new Client(['timeout'  => 10000.0,]);

//ASSIGN json name/value pairs to body
$updateBody['name1'] = $varNum1;
$updateBody['name2'] = $varNum2;
$updateBody['name3'] = $varNum3;
$updateBody['name4'] = $varNum4;
$updateBody['name5'] = $varNum5;
$updateBody['name6'] = $varNum6;
$updateBody['name7'] = $varNum7;

//SEND AND SAVE RESULT TO updateRequestResponse //TAKE NOTE OF: JSON_FORCE_OBJECT //
$updateRequestResponse = $updateRequestClient->post($baseServiceURL, ['headers' => ['Content-Type' => 'application/json', 'Accept' => 'application/json', 'token' => 'test-token'], 'body' => json_encode($updateBody, JSON_FORCE_OBJECT) ]);

$requestResponseCode = $updateRequestResponse->getStatusCode(); // 200?? 

if ($requestResponseCode == "200") {                                                  

echo ("SUCCESS");

}

谢谢你的回答，你是对的。我对我的原始示例进行了一些更改，以使其正常工作。我会把它贴在下面作为答案。
//PREP PAYLOAD (varNum1 coming from elsewhere)
$varNum2 = $q;
$varNum3 = $w;
$varNum4 = $e;
$varNum5 = $r;
$varNum6 = $t;
$varNum7 = 'me';

//THE WEBSERVICE UPDATE BASE URL 
$baseServiceURL = (string)('http://127.0.0.1:8080/service/v1/ws//something/update'); 

$updateRequestClient = new Client(['timeout'  => 10000.0,]);

//ASSIGN json name/value pairs to body
$updateBody['name1'] = $varNum1;
$updateBody['name2'] = $varNum2;
$updateBody['name3'] = $varNum3;
$updateBody['name4'] = $varNum4;
$updateBody['name5'] = $varNum5;
$updateBody['name6'] = $varNum6;
$updateBody['name7'] = $varNum7;

//SEND AND SAVE RESULT TO updateRequestResponse //TAKE NOTE OF: JSON_FORCE_OBJECT //
$updateRequestResponse = $updateRequestClient->post($baseServiceURL, ['headers' => ['Content-Type' => 'application/json', 'Accept' => 'application/json', 'token' => 'test-token'], 'body' => json_encode($updateBody, JSON_FORCE_OBJECT) ]);

$requestResponseCode = $updateRequestResponse->getStatusCode(); // 200?? 

if ($requestResponseCode == "200") {                                                  

echo ("SUCCESS");

}