mysql php脚本只在第一次使用时有效
我有一个脚本可以将公司和类别添加到数据库中,但是它只在第一次工作。当我尝试添加第二个公司时,在通过所有其他错误检查后,它在最终错误检查中失败。类别已成功添加到“类别”表中,但公司及其详细信息未添加到“公司”表中 这可能是代码错误还是数据库构造中的错误 下面是最后的错误检查和mysql查询:mysql php脚本只在第一次使用时有效,php,mysql,mysqli,Php,Mysql,Mysqli,我有一个脚本可以将公司和类别添加到数据库中,但是它只在第一次工作。当我尝试添加第二个公司时,在通过所有其他错误检查后,它在最终错误检查中失败。类别已成功添加到“类别”表中,但公司及其详细信息未添加到“公司”表中 这可能是代码错误还是数据库构造中的错误 下面是最后的错误检查和mysql查询: if (empty($errors)) { // If everything's OK. // Add the company to the database: $q = 'INSERT I
if (empty($errors)) { // If everything's OK.
// Add the company to the database:
$q = 'INSERT INTO companies (category_id, company_name, phone, email, website, address_1, address_2, address_3, postcode, description, image_name) VALUES (?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?)';
$stmt = mysqli_prepare($dbc, $q);
mysqli_stmt_bind_param($stmt, 'issssssssss', $catid, $cn, $p, $e, $w, $a1, $a2, $a3, $pc, $d, $i);
mysqli_stmt_execute($stmt);
// Check the results...
if (mysqli_stmt_affected_rows($stmt) == 1) {
// Print a message:
echo '<p>The company has been added.</p>';
// Rename the image:
$id = mysqli_stmt_insert_id($stmt); // Get the company ID.
rename ($temp, "../../../uploads/$id");
// Clear $_POST:
$_POST = array();
} else { // Error!
echo '<p style="font-weight: bold; color: #C00">Your submission could not be processed due to a system error.</p>';
}
mysqli_stmt_close($stmt);
} // End of $errors IF.
if(空($errors)){//如果一切正常。
//将公司添加到数据库:
$q='插入公司(类别id、公司名称、电话、电子邮件、网站、地址1、地址2、地址3、邮政编码、描述、图像名称)值(?,,,,,,,,,,,,,);
$stmt=mysqli_prepare($dbc,$q);
mysqli_stmt_bind_param($stmt,$issss',$catid,$cn,$p,$e,$w,$a1,$a2,$a3,$pc,$d,$i);
mysqli_stmt_execute($stmt);
//检查结果。。。
如果(mysqli\u stmt\u受影响的行($stmt)==1){
//打印消息:
echo'该公司已被添加。;
//重命名图像:
$id=mysqli\u stmt\u insert\u id($stmt);//获取公司id。
重命名($temp,“../../../uploads/$id”);
//清除$\u帖子:
$\u POST=array();
}否则{//错误!
echo“由于系统错误,无法处理您提交的内容。
”;
}
mysqli_stmt_close($stmt);
}//如果发生错误,则结束$errors。
以下是完整的代码:
<?php
require_once ('../../../mysqli_connect.php');
if (isset($_POST['submitted'])) { // Handle the form.
// Validate the incoming data...
$errors = array();
// Check for a company name:
if (!empty($_POST['company_name'])) {
$cn = trim($_POST['company_name']);
} else {
$errors[] = 'Please enter the company\'s name!';
}
// Check for an image:
if (is_uploaded_file ($_FILES['image']['tmp_name'])) {
// Create a temporary file name:
$temp = '../../../uploads/' . md5($_FILES['image']['name']);
// Move the file over:
if (move_uploaded_file($_FILES['image']['tmp_name'], $temp)) {
echo '<p>The file has been uploaded!</p>';
// Set the $i variable to the image's name:
$i = $_FILES['image']['name'];
} else { // Couldn't move the file over.
$errors[] = 'The file could not be moved.';
$temp = $_FILES['image']['tmp_name'];
}
} else { // No uploaded file.
$errors[] = 'No file was uploaded.';
$temp = NULL;
}
// Validate the category...
if (isset($_POST['category']) && ($_POST['category'] == 'new') ) {
// If it's a new category, add the category to the database...
// Check for a category name...
if (!empty($_POST['category_name'])) {
$catn = trim($_POST['category_name']);
// Add the category to the database:
$q = 'INSERT INTO categories (category_name) VALUES (?)';
$stmt = mysqli_prepare($dbc, $q);
mysqli_stmt_bind_param($stmt, 's', $catn);
mysqli_stmt_execute($stmt);
// Check the results....
if (mysqli_stmt_affected_rows($stmt) == 1) {
echo '<p>The category has been added.</p>';
$catid = mysqli_stmt_insert_id($stmt); // Get the category ID.
} else { // Error!
$errors[] = 'The new category could not be added to the database!';
}
// Close this prepared statement:
mysqli_stmt_close($stmt);
} else { // No category name value.
$errors[] = 'Please enter the category\'s name!';
}
} elseif ( isset($_POST['category']) && ($_POST['category'] == 'existing') && ($_POST['existing'] > 0) ) { // Existing category.
$catid = (int) $_POST['existing'];
} else { // No category selected.
$errors[] = 'Please enter or select the category\'s name!';
}
if (empty($errors)) { // If everything's OK.
// Add the company to the database:
$q = 'INSERT INTO companies (category_id, company_name, image_name) VALUES (?, ?, ?)';
$stmt = mysqli_prepare($dbc, $q);
mysqli_stmt_bind_param($stmt, 'iss', $catid, $cn, $i);
mysqli_stmt_execute($stmt);
// Check the results...
if (mysqli_stmt_affected_rows($stmt) == 1) {
// Print a message:
echo '<p>The company has been added.</p>';
// Rename the image:
$id = mysqli_stmt_insert_id($stmt); // Get the company ID.
rename ($temp, "../../../uploads/$id");
// Clear $_POST:
$_POST = array();
} else { // Error!
echo '<p style="font-weight: bold; color: #C00">Your submission could not be processed due to a system error.</p>';
}
mysqli_stmt_close($stmt);
} // End of $errors IF.
// Delete the uploaded file if it still exists:
if ( isset($temp) && file_exists ($temp) && is_file($temp) ) {
unlink ($temp);
}
} // End of the submission IF.
// Check for any errors and print them:
if ( !empty($errors) && is_array($errors) ) {
echo '<h1>Error!</h1>
<p style="font-weight: bold; color: #C00">The following error(s) occurred:<br />';
foreach ($errors as $msg) {
echo " - $msg<br />\n";
}
echo 'Please reselect the company image and try again.</p>';
}
// Display the form...
?>
我需要将主键指定为自动递增,在本例中是公司id字段 添加详细错误检查的一种简单方法是插入
mysqli_report(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT);
在建立mysqli_连接之前。我需要将主键指定为自动递增,在本例中,它是company_id字段 添加详细错误检查的一种简单方法是插入
mysqli_report(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT);
在建立mysqli_连接之前。MySQL/PHP会出现什么错误?请参阅以了解如何添加错误或
die(mysqli_错误($dbc))代码>在mysqli\u stmt\u执行($stmt)
之后,我得到了以下错误:键“PRIMARY”的重复条目“0”,这说明自动增量无法正常工作?主键是公司表中的公司id,我刚刚添加了mysqli_报告(mysqli_报告错误| mysqli_报告严格)代码>到mysqli_connect上面的代码顶部,现在错误显示为“致命错误:未捕获异常'mysqli_sql_exception',在add_company.php:132堆栈跟踪:#0 add_company.php(132):mysqli_stmt_execute(Object(mysqli_stmt))#1{main}抛出在add_company.php的第132行”MySQL/PHP给出了什么错误?请参阅以了解如何添加错误或die(mysqli_error($dbc))代码>在mysqli\u stmt\u执行($stmt)
之后,我得到了以下错误:键“PRIMARY”的重复条目“0”,这说明自动增量无法正常工作?主键是公司表中的公司id,我刚刚添加了mysqli_报告(mysqli_报告错误| mysqli_报告严格)代码>到mysqli_connect上面的代码顶部,现在错误显示为“致命错误:未捕获异常'mysqli_sql_exception',在add_company.php:132堆栈跟踪:#0 add_company.php(132):mysqli_stmt_execute(Object(mysqli_stmt))#1{main}抛出在add_company.php的第132行”