Php 为什么我得到一个`调用未定义的方法User:：emailExists（）`错误？

我在尝试登录到我的页面时遇到此错误

致命错误：未捕获错误：调用未定义的方法User:：emailExists（）

我不知道为什么，并试图找到一个解决办法，但没有运气到目前为止

据我所知，这将检查电子邮件是否存在（我知道我正在尝试登录的电子邮件存在：-）

以下是我的代码：

$database = new Database();
$db = $database->getConnection();

// initialize objects
$user = new User($db);

// check if email and password are in the database
$user->email=$_POST['email'];

// check if email exists, also get user details using this emailExists() 
method
$email_exists = $user->emailExists(); --> Error at this line

// validate login
if ($email_exists && password_verify($_POST['password'], $user->password) 
&& $user->status==1){

// if it is, set the session value to true
$_SESSION['logged_in'] = true;
$_SESSION['user_id'] = $user->id;
$_SESSION['access_level'] = $user->access_level;
$_SESSION['firstname'] = htmlspecialchars($user->firstname, ENT_QUOTES, 
'UTF-8') ;
$_SESSION['lastname'] = $user->lastname;

// if access level is 'Admin', redirect to admin section
if($user->access_level=='Admin'){
    header("Location: {$home_url}admin/index.php?action=login_success");
}

// else, redirect only to 'Customer' section
else{
    header("Location: {$home_url}index.php?action=login_success");
}
}

// if username does not exist or password is wrong
else{
$access_denied=true;
}
}

抱歉，这是用户类：

<?php
// 'user' object
class User{

// database connection and table name
private $conn;
private $table_name = "users";

// object properties
public $id;
public $firstname;
public $lastname;
public $email;
public $contact_number;
public $address;
public $password;
public $access_level;
public $access_code;
public $status;
public $created;
public $modified;

// constructor
public function __construct($db){
    $this->conn = $db;
}
}
function emailExists(){

// query to check if email exists
$query = "SELECT id, firstname, lastname, access_level, password, status
        FROM " . $this->table_name . "
        WHERE email = ?
        LIMIT 0,1";

// prepare the query
$stmt = $this->conn->prepare( $query );

// sanitize
$this->email=htmlspecialchars(strip_tags($this->email));

// bind given email value
$stmt->bindParam(1, $this->email);

// execute the query
$stmt->execute();

// get number of rows
$num = $stmt->rowCount();

// if email exists, assign values to object properties for easy access and 
use for php sessions
if($num>0){

    // get record details / values
    $row = $stmt->fetch(PDO::FETCH_ASSOC);

    // assign values to object properties
    $this->id = $row['id'];
    $this->firstname = $row['firstname'];
    $this->lastname = $row['lastname'];
    $this->access_level = $row['access_level'];
    $this->password = $row['password'];
    $this->status = $row['status'];

    // return true because email exists in the database
    return true;
}

// return false if email does not exist in the database
return false;
}

---

在用户类中查找此行
公共函数uu构造（$db）{$this->conn=$db；
}
}
移除最后一个大括号，实际上是在构造函数之后直接关闭类。在文件末尾，您需要添加另一个}以确保在结尾关闭类
您需要向我们显示具有emailExists函数的用户类，我已更新了我的问题：-）这就是明确说明方法是
public
有帮助的地方。我现在真的觉得：-（谢谢！！现在一切都很好。我现在可以继续我的生活了：-！！欢迎你，请接受正确的答案：）我刚刚有。两分钟后我才能接受。再次感谢！！