Php 如果与许多其他的if只工作到3次尝试,当它达到4次时不工作 $oride=''; $count=“25”; $origin=$_POST[“origin”]; $destinataion=$_POST[“destination”]; $oride=($destination=$\u POST[“destination”]- $origin=$_POST[“origin”]; if($oride
Php 如果与许多其他的if只工作到3次尝试,当它达到4次时不工作 $oride=''; $count=“25”; $origin=$_POST[“origin”]; $destinataion=$_POST[“destination”]; $oride=($destination=$\u POST[“destination”]- $origin=$_POST[“origin”]; if($oride,php,if-statement,Php,If Statement,=是赋值运算符。您需要=或==(如果数据类型也需要相等)进行比较 $oride=''; $count = "25"; $origin = $_POST["origin"]; $destinataion = $_POST["destination"]; $oride = ($destination = $_POST["destination"] - $origin= $_POST["origin"]); if ($oride <="
=
是赋值运算符。您需要=
或==
(如果数据类型也需要相等)进行比较
$oride='';
$count = "25";
$origin = $_POST["origin"];
$destinataion = $_POST["destination"];
$oride = ($destination = $_POST["destination"] -
$origin= $_POST["origin"]);
if ($oride <="0"){
echo "invalid";
}
elseif ($oride <="15"){
echo $count;
}
elseif ($oride ="16"){
echo $count + "1";
}
elseif ($oride ="17"){
echo $count + "2";
}
$oride='';
$count=“25”;
$origin=$_POST[“origin”];
$destinataion=$_POST[“destination”];
$oride=($destination=$\u POST[“destination”]-
$origin=$_POST[“origin”];
如果($oride),它应该是==
,而不是=
。提示:$x=y
分配。请参阅ty bro,这很有帮助
$oride='';
$count = "25";
$origin = $_POST["origin"];
$destinataion = $_POST["destination"];
$oride = ($destination = $_POST["destination"] -
$origin= $_POST["origin"]);
if ($oride <="0"){
echo "invalid";
}
elseif ($oride <="15"){
echo $count;
}
elseif ($oride =="16"){
echo $count + "1";
}
elseif ($oride =="17"){
echo $count + "2";
}