博文'；t在php中插入值

你好！我试图将一些数据保存到我的数据库中，但它不会工作，但不会显示任何类型的错误。请告诉我我做错了什么。我试图找出错误，但我认为另一双眼睛和大脑真的可以帮我。谢谢！：）

这是我的密码

 <?php
 $user_name = "root";
 $password = "";
 $database = "db_tocode";
 $server = "127.0.0.1";
 $content = "content_temp1";

$uname = $_GET['username'];

$db_handle = mysql_connect($server, $user_name, $password);
$db_found = mysql_select_db($database, $db_handle);

$header = $_POST['header'];
$title1 = $_POST['title1'];
$content1 = $_POST['content1'];
$title2 = $_POST['title2'];
$content2 = $_POST['content2'];
$title3 = $_POST['title3'];
$content3 = $_POST['content3'];
$title4 = $_POST['title4'];
$content4 = $_POST['content4'];
$title5 = $_POST['title5'];
$content5 = $_POST['content5'];
$title6 = $_POST['title6'];
$content6 = $_POST['content6'];
$title7 = $_POST['title7']; 
$content7 = $_POST['content7'];
$title8 = $_POST['title8'];
$content8 = $_POST['content8'];
$title9 = $_POST['title9'];
$content9 = $_POST['content9'];
$title10 = $_POST['title10'];
$content10 = $_POST['content10'];
$content11 = $_POST['content11'];

if ($db_found) {

   $SQL="INSERT INTO $content (user_uname, header, title1, content1, title2, content2,                  title3,content3,title4, content4, title5, content5, title6, content6, title7, content7, title8, content8, title9, content9, title10, content10, content11) VALUES('$uname',              ' $header', '$title1', '$content1', '$title2', '$content2', '$title3', '$content3', '$title4', '$content4', '$title5', '$content5', '$title6', '$content6', '$title7', '$content7', '$title8', '$content8', '$title9', '$content9', '$title10', '$content10',   '$content11')";

header('Location:1stTemplate/index.php');

}   
else {

print "Database NOT Found ";
mysql_close($db_handle);

}

?>

执行您的查询：

$query = mysql_query($sql);

并且您正在使用localhost，因此您的服务器名称将

$server = "localhost";

---

并使用

mysqli

而不是

mysql

危险：您正在使用并且应该使用。您还容易受到以下问题的影响：一个现代API会使您从.echo$sql更轻松，并在phpmyadmin中手动触发该查询，然后检查是否存在任何查询errors@krishna-表名为

content\u temp1

$

表示PHP中变量的开头。@krishna-否。PHP双引号字符串插入变量。删除和删除文本以及添加一堆串联运算符只会造成混乱。@krishna-您似乎不知道PHP字符串中的变量插值。我建议你阅读手册中关于的章节。非常感谢。哈哈。我早就知道了！谢谢你的帮助！！