在PHP中连接3个表以生成一个数组

我在mySQL中遇到了一个查询问题

实际上，我的mySQL查询如下所示：

$contact = array (
    "client"  => array("KDX_Id" => 44, "KDX_Name" => "Luka"),
    "company" => array("KDX_Id" => 46, "KDX_Company" => "Google"),
    "billing"   => array() // Noting here because no billing contact was link
);

\u发票

表格

|--------|---------------|
| IVC_Id | IVC_BookingId |
|--------|---------------|
| 1      | 99            |
|--------|---------------|

|--------|--------------|---------------|---------------|
| BOO_Id | BOO_ClientId | BOO_CompanyId | BOO_BillingId |
|--------|--------------|---------------|---------------|
| 99     | 44           | 46            | 0             |
|--------|--------------|---------------|---------------|

|--------|----------|----------|-------------|
| KDX_Id | KDX_Type | KDX_Name | KDX_Company |
|--------|----------|----------|-------------|
| 44     | client   | Luka     |             |
| 46     | company  |          | Google      |
| 78     | billing  | Georgia  |             |
|--------|----------|----------|-------------|

\uuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuu

|--------|---------------|
| IVC_Id | IVC_BookingId |
|--------|---------------|
| 1      | 99            |
|--------|---------------|

|--------|--------------|---------------|---------------|
| BOO_Id | BOO_ClientId | BOO_CompanyId | BOO_BillingId |
|--------|--------------|---------------|---------------|
| 99     | 44           | 46            | 0             |
|--------|--------------|---------------|---------------|

|--------|----------|----------|-------------|
| KDX_Id | KDX_Type | KDX_Name | KDX_Company |
|--------|----------|----------|-------------|
| 44     | client   | Luka     |             |
| 46     | company  |          | Google      |
| 78     | billing  | Georgia  |             |
|--------|----------|----------|-------------|

\uuu Kardex
表格

|--------|---------------|
| IVC_Id | IVC_BookingId |
|--------|---------------|
| 1      | 99            |
|--------|---------------|

|--------|--------------|---------------|---------------|
| BOO_Id | BOO_ClientId | BOO_CompanyId | BOO_BillingId |
|--------|--------------|---------------|---------------|
| 99     | 44           | 46            | 0             |
|--------|--------------|---------------|---------------|

|--------|----------|----------|-------------|
| KDX_Id | KDX_Type | KDX_Name | KDX_Company |
|--------|----------|----------|-------------|
| 44     | client   | Luka     |             |
| 46     | company  |          | Google      |
| 78     | billing  | Georgia  |             |
|--------|----------|----------|-------------|


如何链接这3个表？
我在决赛中需要的是这样一个数组：

$contact = array (
    "client"  => array("KDX_Id" => 44, "KDX_Name" => "Luka"),
    "company" => array("KDX_Id" => 46, "KDX_Company" => "Google"),
    "billing"   => array() // Noting here because no billing contact was link
);

我从查询开始：

SELECT *
 FROM ___Invoices 
 JOIN ___Bookings 
 ON ___Invoices.IVC_BookingId=___Bookings.BOO_Id
 JOIN ___Kardex 
 ON ___Bookings.BOO_ClientId =___Kardex.KDX_Id
 OR ___Bookings.BOO_CompanyId =___Kardex.KDX_Id
 OR ___Bookings.BOO_CompanyId =___Kardex.KDX_Id
 WHERE IVC_Id=1

但它不起作用

请问有什么帮助吗

谢谢。
使用联合操作。只有当所有3个查询返回相同数量的结果时，这才有效。像这样：

SELECT KDX_Id, KDX_Type, KDX_Name FROM (
    (SELECT K.KDX_Id, K.KDX_Type, K.KDX_Name, B.BOO_Id
     FROM ___Kardex AS K
     JOIN ___Bookings AS B ON K.KDX_Id = B.BOO_ClientId)
   UNION
    (SELECT K.KDX_Id, K.KDX_Type, K.KDX_Company, B.BOO_Id
     FROM ___Kardex AS K
     JOIN ___Bookings AS B ON K.KDX_Id = B.BOO_CompanyId)
   UNION
    (SELECT K.KDX_Id, K.KDX_Type, K.KDX_Name, B.BOO_Id
     FROM ___Kardex AS K
     JOIN ___Bookings AS B ON K.KDX_Id = B.BOO_BillingId) ) AS TEMP
JOIN ___Invoices AS I ON I.IVC_BookingId = TEMP.BOO_ID
WHERE I.IVC_Id = 1

结果将类似于：

ID    TYPE      NAME (or company)
44    client    Luka             
46    company   Google          

然后在PHP代码中，循环结果的每一行，并使用类型（第二列）填充数组

$contacts = array($results[1] => array($results[0] => $results[1]));

注意：我测试了查询，而不是PHP，但您知道了

编辑说明：联合的结果现在定义为临时。然后将TEMP连接到表uuuu Invoices，以允许选择要筛选的发票。
只是添加了
其中IVC_uid=1
部分。“不工作”并没有告诉我们太多。您是否遇到错误？您使用什么php代码将返回的行格式化为首选的php格式？至少有一个问题是，当您多次加入同一个表时，在php中选择列名时，最后一行的值将覆盖前面的行。您需要使用别名来防止这种情况。我没有任何错误。查询工作正常，但我无法获得所需的输出。您好，谢谢您的回复。是否可能遗漏了选择我的发票的
WHERE
部分？