Php 我无法在我的网页上显示我的视频_Php_Html_Mysql_Video

Php 我无法在我的网页上显示我的视频

php html mysql video

Php 我无法在我的网页上显示我的视频,php,html,mysql,video,Php,Html,Mysql,Video,我正在使用php从MYSQL数据库加载视频并将其显示在网页上。视频存储为URL以节省数据库空间。每当我加载网页时，我都会得到播放视频的控件，仅此而已。如何让视频显示出来 <?php session_start(); $connect = mysqli_connect("localhost", "root", "root", "videodata"); ?> <!DOCTYPE html> <html> <head> <title&

我正在使用php从MYSQL数据库加载视频并将其显示在网页上。视频存储为URL以节省数据库空间。每当我加载网页时，我都会得到播放视频的控件，仅此而已。如何让视频显示出来

<?php
session_start();
$connect = mysqli_connect("localhost", "root", "root", "videodata");
?>
<!DOCTYPE html>
<html>
  <head>
    <title>Starter Project</title>
  <meta charset="utf-8">
  <title>HTML5 Audio</title>

    </head>
    <body>

    <?php
  $query = "SELECT * FROM videos";
  $result = mysqli_query($connect, $query);
  if(mysqli_num_rows($result) > 0)
  {
    while($row = mysqli_fetch_array($result))
    {
      ?>
  <video width="320" height="240" controls>
      <source src="<?php echo $row['title']; ?>" type="video/mp4">
      Your browser does not support the video tag.
  </video>
<?php
}
}
?>

  </body>
</html>


起步项目
HTML5音频

标记不需要结束标记
确保文件包含在从$row['title']
返回的路径中
<?php 
session_start(); 
$connect = mysqli_connect("localhost", "root", "root", "videodata"); 
?> 
<!DOCTYPE html> 
<html> 
 <head> 
   <title>Starter Project</title> 
   <meta charset="utf-8"> 
   <title>HTML5 Audio</title> 
 </head> 
 <body> 
 <?php 
  $query = "SELECT * FROM videos"; 
  $result = mysqli_query($connect, $query);
  if(mysqli_num_rows($result) > 0) {
    while($row = mysqli_fetch_array($result)) { 
 ?> 
     <video width="320" height="240" controls> 
      <source src="<?php echo $row['title'];?>" type="video/mp4">
      Your browser does not support the video tag.
     </video> 
  <?php } } ?>
 </body> 
</html>

另外，$row[title]
应更改为$row['title']

<?php 
session_start(); 
$connect = mysqli_connect("localhost", "root", "root", "videodata"); 
?> 
<!DOCTYPE html> 
<html> 
 <head> 
   <title>Starter Project</title> 
   <meta charset="utf-8"> 
   <title>HTML5 Audio</title> 
 </head> 
 <body> 
 <?php 
  $query = "SELECT * FROM videos"; 
  $result = mysqli_query($connect, $query);
  if(mysqli_num_rows($result) > 0) {
    while($row = mysqli_fetch_array($result)) { 
 ?> 
     <video width="320" height="240" controls> 
      <source src="<?php echo $row['title'];?>" type="video/mp4">
      Your browser does not support the video tag.
     </video> 
  <?php } } ?>
 </body> 
</html>


启动项目
HTML5音频
除非有多种类型的视频，否则可以使用视频标记的src属性：

如果您查看页面的源代码，您会看到视频的“src”是什么？请尝试
。仍然没有任何内容。Chris视频的src应该是，但它没有显示任何内容。var_dump
您的$row请问，它是否包含您需要的数据？是的，它确实给了我视频的url。如果有帮助的话，我得到的是：数组（4）{[0]=>string（1）“1”[“id”]=>string（1）“1”[1]=>string（66）”/Users/connor/Desktop/homeVideoStreamingStuff/XOPIntro.mp4“[“title”]=>string（66）”/Users/connor/Desktop/homeVideoStreamingStuff/XOPIntro.mp4”}
<?php
$getVideo = "select * from videos";

$getVideoRes = mysqli_query($con, $getVideo);

$details = mysqli_fetch_assoc($getVideoRes);

$videoUrl = $details['videoUrl'];
?>

<body>
        <video id="lecVideo" width="340" height="200" controls>
        
        <source src="videos/<?php echo $videoUrl;?>" type="video/mp4">
        
        </video>

</body>