Php 查询和列出管理级别-连接两个表
我想创建一个管理组,它可以通过这个级别表访问数据, 低级别无法查看高级别的数据 0 => 3Php 查询和列出管理级别-连接两个表,php,mysql,Php,Mysql,我想创建一个管理组,它可以通过这个级别表访问数据, 低级别无法查看高级别的数据 0 => 3 高=>低 用户表: --------------------- uid gid uname --------------------- 110 4 Jacky =>means {gname: art_admin ,level: 2} 111 1 Niky =>means {gname: site_admin ,level: 0} 11
高=>低 用户表:
---------------------
uid gid uname
---------------------
110 4 Jacky =>means {gname: art_admin ,level: 2}
111 1 Niky =>means {gname: site_admin ,level: 0}
112 4 Cupe =>means {gname: art_admin ,level: 2}
113 2 Nancy =>means {gname: gen_admin ,level: 1}
113 5 Joe =>means {gname: admin ,level: 3}
分组表:
---------------------
gid gname level
---------------------
1 site_admin 0
2 gen_admin 1
3 sys_admin 1
4 art_admin 2
5 admin 3
这意味着杰基属于“艺术行政”,他的级别为“2”。
因此,当他查看all user表时,它只显示2以下的级别
$uid = 110 ;// Assume I'm Jacky
$result = mysql_query("
SELECT
user.uname from user
WHERE
[ group.level >= Jacky's level ]
";);
while($row = mysql_fetch_array($result)){
echo $row['uname']." , ";
}
它应该会回来
Jacky , Cupe , Joe
这就是你要找的问题吗
select u.uname
from user u join
groups g
on u.gid = g.gid
where g.level >= (select g2.level
from user u2 join
groups g2
on u2.gid = g2.gid
where u2.uname = 'Jacky'
);
mysql_*已弃用,请使用mysqli_*或PDOarter确保接受正确答案!谢谢,我现在正在尝试使用PDO