Mysql SQL WHERE不过滤我的结果

我想筛选出小于3的结果，但每当我添加WHERE语句时，查询就会失败。我的问题出了什么问题？我正在使用MySQL Workbench 3.7

SELECT c.name, COUNT(DISTINCT s.product_id) AS veggies  
FROM sales AS s
INNER JOIN customers AS c
ON c.id=s.customer_id
GROUP BY s.customer_id
WHERE veggies > 2"

谢谢！

---

Yoni

其中的

应该是
具有
：

SELECT c.name, COUNT(DISTINCT s.product_id) AS veggies
FROM sales s INNER JOIN
     customers c
     ON c.id = s.customer_id
GROUP BY s.customer_id
HAVING veggies > 2;

您的查询生成了语法错误（即未运行），或者在
分组依据
处停止，并忽略了
其中
需要在
分组依据
而非
其中
之后使用
HAVING
：

SELECT 
    c.name, COUNT(DISTINCT s.product_id) AS veggies
FROM 
    sales AS s
    INNER JOIN customers AS c ON c.id = s.customer_id
GROUP BY 
    s.customer_id
HAVING 
    veggies > 2

。（单击此链接将进入回答此问题的页面）

希望这能奏效

SELECT c.name, COUNT(DISTINCT s.product_id) AS veggies'  
FROM sales AS s
INNER JOIN customers AS c
ON c.id=s.customer_id
WHERE veggies > "2"
GROUP BY s.customer_id

通过交换这两行

GROUP BY s.customer_id
WHERE veggies > "2"

分组总是在WHERE之后

除此之外，您还缺少一个大约2的开场白

WHERE veggies > 2"

以及在第一行末尾不必要的单引号（'）
 查询必须符合语法