Php 如何找到从第一次出现到最后一次出现的数组变量范围？

问题：

array(
    [0] => stdClass Object ( [booking] => )
    [1] => stdClass Object ( [booking] => )
    [2] => stdClass Object ( [booking] => 2014-12-08 09:00:00 )
    [3] => stdClass Object ( [booking] => )
    [4] => stdClass Object ( [booking] => )
    [5] => stdClass Object ( [booking] => 2014-12-08 10:30:00 )
    [6] => stdClass Object ( [booking] => )
    [7] => stdClass Object ( [booking] => )
    [8] => stdClass Object ( [booking] => )
)

array(
    [2] => stdClass Object ( [booking] => 2014-12-08 09:00:00 )
    [3] => stdClass Object ( [booking] => )
    [4] => stdClass Object ( [booking] => )
    [5] => stdClass Object ( [booking] => 2014-12-08 10:30:00 )
)

一个人从当天的第一次约会开始，直到当天的最后一次约会为止，都会得到报酬——其间包括未预订的时间

示例数组如下所示：

array(
    [0] => stdClass Object ( [booking] => )
    [1] => stdClass Object ( [booking] => )
    [2] => stdClass Object ( [booking] => 2014-12-08 09:00:00 )
    [3] => stdClass Object ( [booking] => )
    [4] => stdClass Object ( [booking] => )
    [5] => stdClass Object ( [booking] => 2014-12-08 10:30:00 )
    [6] => stdClass Object ( [booking] => )
    [7] => stdClass Object ( [booking] => )
    [8] => stdClass Object ( [booking] => )
)

array(
    [2] => stdClass Object ( [booking] => 2014-12-08 09:00:00 )
    [3] => stdClass Object ( [booking] => )
    [4] => stdClass Object ( [booking] => )
    [5] => stdClass Object ( [booking] => 2014-12-08 10:30:00 )
)

所需输出：

array(
    [0] => stdClass Object ( [booking] => )
    [1] => stdClass Object ( [booking] => )
    [2] => stdClass Object ( [booking] => 2014-12-08 09:00:00 )
    [3] => stdClass Object ( [booking] => )
    [4] => stdClass Object ( [booking] => )
    [5] => stdClass Object ( [booking] => 2014-12-08 10:30:00 )
    [6] => stdClass Object ( [booking] => )
    [7] => stdClass Object ( [booking] => )
    [8] => stdClass Object ( [booking] => )
)

array(
    [2] => stdClass Object ( [booking] => 2014-12-08 09:00:00 )
    [3] => stdClass Object ( [booking] => )
    [4] => stdClass Object ( [booking] => )
    [5] => stdClass Object ( [booking] => 2014-12-08 10:30:00 )
)

计数=4

---

如何提取所需的数据集？

过早地提出了我认为可能有更有效的方法来实现这一点，但通过下面的两个循环运行数组时，删除了各自第一次出现的前导和训练空白项：

for($i=0; $i < count($timesheet); $i++){
    if ($timesheet[$i]['booking'] == 0) {
        unset($timesheet[$i]);
    } else {
        break;
    }
}

$timesheet = array_values($timesheet);

for($i=count($timesheet)-1; $i > 0; $i--){
    if ($timesheet[$i]['booking'] == 0) {
        unset($timesheet[$i]);
    } else {
        break;
    }
}

for（$i=0；$i0；$i--）{
如果（$timesheet[$i]['booking']==0）{
未设置（$timesheet[$i]）；
}否则{
打破
}
}

我需要制作一份“时间表”，基本上是从第一次约会到最后一次约会的列表。我已经能够逐步通过并放弃前两次约会。。。当我输入这个时，我可能只需要向后跨过数组，然后丢弃那些我不能做的？笑面掌