Php 如何将数组数据从json字段显示到刀片视图？

我创建了一个json字段来存储数组数据

仓库表结构

在仓库模型中，我使用$cast存储阵列数据

protected $casts = [
    'produce_stored' => 'array'
];

在仓库控制器中-索引方法

$warehouses = DB::table('warehouses')
                ->join('regions', 'regions.id', '=', 'warehouses.region_id')
                ->join('districts', 'districts.id', '=', 'warehouses.district_id')
                ->join('users', 'users.id', '=', 'warehouses.agent_assigned')
                ->select(
                    'warehouses.id',
                    'warehouses.name as warehouseName',
                    'warehouses.ownership_type',
                    'warehouses.capacity',
                    'warehouses.produce_stored',  // json field with array data
                    'regions.name as regionName', 
                    'districts.name as districtName',
                    'users.name as agent_assigned',
                    'warehouses.status'
                    )
                ->get();

return view('admin.warehouses.index', compact('warehouses'));

在刀片视图中

{{ $warehouse->produce_stored }}

这是浏览器中的输出

["1", "2"]

当我尝试在数组中循环以获取产品ID以加载产品名称时

@foreach ($warehouse->produceStored as $produce)
    {{$produce}}
@endforeach

上面的代码抛出了一个错误

Invalid argument supplied for foreach()

如何从Product_存储字段中获取产品ID？

您有两个选择：

 <?php $warehouse->produceStored = json_decode($warehouse->produceStored, false); ?>

2-正如Autista_z在评论中所说：

$warehouses = Warehouse::query()
                ->join('regions', 'regions.id', '=', 'warehouses.region_id')
                ->join('districts', 'districts.id', '=', 'warehouses.district_id')
                ->join('users', 'users.id', '=', 'warehouses.agent_assigned')
                ->select(
                    'warehouses.id',
                    'warehouses.name as warehouseName',
                    'warehouses.ownership_type',
                    'warehouses.capacity',
                    'warehouses.produce_stored',  // json field with array data
                    'regions.name as regionName', 
                    'districts.name as districtName',
                    'users.name as agent_assigned',
                    'warehouses.status'
                    )
                ->get();

---

注意：如果它们不相同，请用模型名称替换仓库…

问题是，您使用的不是模型，而是DB调用。在他的情况下，演员没有被称为。将

DB:：table（'warehouses'）

替换为模型调用，

\App\Warehouse:：select…

（正确的模型放置），现在产品ID已列出。如何检索产品名称？我认为您应该在将其发送到视图之前将其加载到控制器中

$warehouses = Warehouse::query()
                ->join('regions', 'regions.id', '=', 'warehouses.region_id')
                ->join('districts', 'districts.id', '=', 'warehouses.district_id')
                ->join('users', 'users.id', '=', 'warehouses.agent_assigned')
                ->select(
                    'warehouses.id',
                    'warehouses.name as warehouseName',
                    'warehouses.ownership_type',
                    'warehouses.capacity',
                    'warehouses.produce_stored',  // json field with array data
                    'regions.name as regionName', 
                    'districts.name as districtName',
                    'users.name as agent_assigned',
                    'warehouses.status'
                    )
                ->get();