PHP MySQL输出两条SQL Select语句

我想将以下两个查询合并为一个查询，日期是第一列。我遇到的问题是子查询的条件不同，第二个查询可能没有每个月的值。我已经在不同的页面上运行了它们，因此为什么这两个页面上的AS num_custs是相同的

我用SQL尝试了几种不同的方法，但到目前为止都失败了。我最初的想法是在SQL中使用UNION，但那不起作用。我认为我尝试用SQL而不是PHP来实现这一点是正确的

第一个问题是我应该使用哪个SQL命令来实现这一点

希望一切都有意义

问题1：

            SELECT * , COUNT( entity_id ) AS num_custs
                FROM (

                SELECT e. * , e.created_at AS abc123, o.status, o.total_invoiced, o.shipping_description, o.subtotal_incl_tax, MAX( o.created_at ) AS last_order_date
                FROM mg_customer_entity AS e
                LEFT JOIN mg_sales_flat_order AS o ON o.customer_id = e.entity_id
                WHERE e.entity_type_id =  '1'
                AND o.status NOT LIKE  'canceled'
                AND o.status NOT LIKE  'closed'
                AND o.status NOT LIKE  'fraud'
                AND o.status NOT LIKE  'holded'
                AND o.status NOT LIKE  'paypal_canceled_reversal'
                AND e.store_id
                BETWEEN 1 
                AND 2 
                AND o.total_invoiced IS NOT NULL 
                AND o.subtotal_incl_tax IS NOT NULL 

                GROUP BY e.entity_id
                HAVING last_order_date IS NOT NULL

                )sub_query
                GROUP BY YEAR( abc123 ) , MONTH( abc123 )
                ORDER BY abc123 DESC

问题2：

            SELECT * , COUNT( entity_id ) AS num_custs
                FROM (

                SELECT e. * , e.created_at AS abc123, o.status, o.total_invoiced, o.shipping_description, o.subtotal_incl_tax, MAX( o.created_at ) AS last_order_date
                FROM mg_customer_entity AS e
                LEFT JOIN mg_sales_flat_order AS o ON o.customer_id = e.entity_id
                WHERE e.entity_type_id =  '1'
                AND o.status NOT LIKE  'canceled'
                AND o.status NOT LIKE  'closed'
                AND o.status NOT LIKE  'fraud'
                AND o.status NOT LIKE  'holded'
                AND o.status NOT LIKE  'paypal_canceled_reversal'
                AND e.store_id
                BETWEEN 1 
                AND 2 
                AND o.total_invoiced IS NOT NULL 
                AND o.subtotal_incl_tax IS NOT NULL 

                GROUP BY e.entity_id
                HAVING last_order_date >= DATE_SUB( CURDATE( ) , INTERVAL 91 DAY )
                AND last_order_date IS NOT NULL

                )sub_query
                GROUP BY YEAR( abc123 ) , MONTH( abc123 )
                ORDER BY abc123 DESC

---

如果您提到希望将日期作为第一个结果，则可以指定所有字段，也可以将其添加到前面

如果使用PHP构建查询，则可以轻松地插入额外的条件

将在中的“%s”位置插入条件

---

我希望我正确地解释了你的问题。

谢谢你的回答，如果你有超过1美元的收入，会发生什么？可能吗？还有，如何循环每一行？可以有一个select语句或多个if语句将“having”条件收集到一个数组中

$having[]=“和某个条件”可以与
$having\u string=内爆（“”，$having）
    // set $limit_order_date depending on the page

    $having = '';

    if ( true === $limit_order_date ) {
        $having = 'AND last_order_date >= DATE_SUB( CURDATE( ) , INTERVAL 91 DAY )';
    }


    $sql = sprintf("
        SELECT abc123,
               * ,
               COUNT( entity_id ) AS num_custs
          FROM (
            SELECT e. *,
                   e.created_at AS abc123,
                   o.status,
                   o.total_invoiced,
                   o.shipping_description,
                   o.subtotal_incl_tax,
                   MAX( o.created_at ) AS last_order_date
              FROM mg_customer_entity AS e
         LEFT JOIN mg_sales_flat_order AS o
                ON o.customer_id = e.entity_id
             WHERE e.entity_type_id =  '1'
               AND o.status NOT LIKE  'canceled'
               AND o.status NOT LIKE  'closed'
               AND o.status NOT LIKE  'fraud'
               AND o.status NOT LIKE  'holded'
               AND o.status NOT LIKE  'paypal_canceled_reversal'
               AND e.store_id BETWEEN 1 AND 2
               AND o.total_invoiced IS NOT NULL
               AND o.subtotal_incl_tax IS NOT NULL
          GROUP BY e.entity_id
            HAVING last_order_date IS NOT NULL %s
                )sub_query
     GROUP BY YEAR( abc123 ),
              MONTH( abc123 )
     ORDER BY abc123 DESC",
        $having
    );