Php Symfony 2-尝试从同一类中的另一个方法获取属性
正如您在下面的代码中看到的,我正在尝试进行子导航。我想从头开始,而不是使用捆绑包,因为我将此作为学习练习。我已经到了一个地步,我想我已经差不多把它破解了。我现在只需要访问subNavAction()内部的navAction()db查询的结果 我已经设法做到了“echo self::navAction($sector);”这会再次显示完整的导航,但我似乎无法访问查询中的单个项目。我实际上需要做的是循环遍历navAction()的结果,并获得所有包含子项的项的结果 我对OOPHP(虽然我对程序非常熟悉)和Symfony/Doctrine非常陌生,所以您能给我的答案越全面越好Php Symfony 2-尝试从同一类中的另一个方法获取属性,php,oop,symfony,doctrine,dql,Php,Oop,Symfony,Doctrine,Dql,正如您在下面的代码中看到的,我正在尝试进行子导航。我想从头开始,而不是使用捆绑包,因为我将此作为学习练习。我已经到了一个地步,我想我已经差不多把它破解了。我现在只需要访问subNavAction()内部的navAction()db查询的结果 我已经设法做到了“echo self::navAction($sector);”这会再次显示完整的导航,但我似乎无法访问查询中的单个项目。我实际上需要做的是循环遍历navAction()的结果,并获得所有包含子项的项的结果 我对OOPHP(虽然我对程序非常熟
//Render Navigation
public function navAction($sector)
{
$em = $this->getDoctrine()->getManager();
$query = $em->createQuery(
"SELECT DISTINCT p.pageName, p.pageParent
FROM styleGuideBundle:pages p
WHERE p.pageSector LIKE :sector
AND p.pageType = 2"
);
$query->setParameter(':sector', '%'.$sector.'%');
$navItems = $query->getResult();
if (!$navItems) throw $this->createNotFoundException('Unable to find any pages under this category');
return $this->render(
'styleGuideBundle:Partial:peNav.html.twig',
array(
'navItems' => $navItems,
'sector' => $sector
)
);
}
//Render SubNavigation
public function subnavAction($sector)
{
echo self::navAction($sector); // This line is where I got stuck.
$em = $this->getDoctrine()->getManager();
$query = $em->createQuery(
"SELECT DISTINCT p.pageName, p.pageParent
FROM styleGuideBundle:pages p
WHERE p.pageSector LIKE :sector
AND p.pageType = 2"
);
$query->setParameter(':sector', '%'.$sector.'%');
$navItems = $query->getResult();
if (!$navItems) throw $this->createNotFoundException('Unable to find any pages under this category');
return $this->render(
'styleGuideBundle:Partial:peNav.html.twig',
array(
'navItems' => $navItems,
'sector' => $sector
)
);
}
这不是最好的解决方案,但您可以创建一个对象变量$this->navItems
PageController extends Controller {
public $navItems = null;
//Render Navigation
public function navAction($sector)
{
$em = $this->getDoctrine()->getManager();
$query = $em->createQuery(
"SELECT DISTINCT p.pageName, p.pageParent
FROM styleGuideBundle:pages p
WHERE p.pageSector LIKE :sector
AND p.pageType = 2"
);
$query->setParameter(':sector', '%'.$sector.'%');
$this->navItems = $query->getResult();
if (!$this->navItems) throw $this->createNotFoundException('Unable to find any pages under this category');
return $this->render(
'styleGuideBundle:Partial:peNav.html.twig',
array(
'navItems' => $this->navItems,
'sector' => $sector
)
);
}
//Render SubNavigation
public function subnavAction($sector)
{
$this->navAction($sector);
var_dump($this->navItems);
$em = $this->getDoctrine()->getManager();
$query = $em->createQuery(
"SELECT DISTINCT p.pageName, p.pageParent
FROM styleGuideBundle:pages p
WHERE p.pageSector LIKE :sector
AND p.pageType = 2"
);
$query->setParameter(':sector', '%'.$sector.'%');
$navItems = $query->getResult();
if (!$navItems) throw $this->createNotFoundException('Unable to find any pages under this category');
return $this->render(
'styleGuideBundle:Partial:peNav.html.twig',
array(
'navItems' => $navItems,
'sector' => $sector
)
);
}
请看,这就是我在谷歌搜索后应该做的,但它会导致以下错误:注意:未定义属性:StyleGuideBundle\Controller\PageController::$navItems in/Volumes/Projects/styleguide/site/Guidelines/src/StyleGuideBundle/Controller/PageController.php第104行只要在Controller:-->类中创建它PageController扩展控制器{$this->navItems=null;…它也不喜欢这样:“FatalErrorException:Parse:语法错误,意外的“$this”(t_变量),期望函数(t_函数)”我像这样尝试“public$navItems=null”;错误改为:“警告:为foreach()提供的参数无效”很抱歉,是这样的:public$navItems=null;现在您可以在控制器中获得$this->navItems变量。请尝试打印($this->navItems);