Php MySQL，使用内部联接的更新查询以静默方式失败

我有一个使用内部联接的MySQL查询更新不起作用，而类似的使用内部联接的select查询工作得很好

工作选择查询

SELECT fa.tax_rate, efa.entity_id
FROM water_civicrmv2.civicrm_financial_account as fa
    INNER JOIN water_civicrmv2.civicrm_entity_financial_account efa ON efa.financial_account_id = fa.id 
    INNER JOIN water_civicrmv2.civicrm_option_value cov ON cov.value = efa.account_relationship
    INNER JOIN water_civicrmv2.civicrm_option_group cog ON cog.id = cov.option_group_id
    WHERE efa.entity_table = 'civicrm_financial_type'
    AND cov.name = 'Sales Tax Account is'
    AND cog.name = 'account_relationship'
    AND fa.is_active = 1

更新查询失败

 UPDATE water_civicrmv2.civicrm_financial_account as fa
    INNER JOIN water_civicrmv2.civicrm_entity_financial_account efa ON efa.financial_account_id = fa.id 
    INNER JOIN water_civicrmv2.civicrm_option_value cov ON cov.value = efa.account_relationship
    INNER JOIN water_civicrmv2.civicrm_option_group cog ON cog.id = cov.option_group_id
    SET fa.tax_rate = '123123' 
    WHERE efa.entity_table = 'civicrm_financial_type'
    AND cov.name = 'Sales Tax Account is'
    AND cog.name = 'account_relationship'
    AND fa.is_active = 1

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我真的不知道为什么它会无声地失败，因为没有语法错误，只是什么也没发生

更改您的更新SQL，以便更新的对象仅为单个表水\u civicrmv2.civicrm\u财务\u帐户：

 UPDATE water_civicrmv2.civicrm_financial_account as fa
    SET fa.tax_rate = '123123' 
    WHERE fa.id = 
          (SELECT fa.id
             FROM water_civicrmv2.civicrm_entity_financial_account efa
             INNER JOIN water_civicrmv2.civicrm_option_value cov ON cov.value = efa.account_relationship
             INNER JOIN water_civicrmv2.civicrm_option_group cog ON cog.id = cov.option_group_id
             WHERE efa.financial_account_id = fa.id 
               AND efa.entity_table = 'civicrm_financial_type'
               AND cov.name = 'Sales Tax Account is'
               AND cog.name = 'account_relationship'
               AND fa.is_active = 1)

---

如果这个选择有效，我就吃我的短裤。如果我已经更新了问题，请再看一看。如果解释器没有抛出任何错误，那一定是数据问题。我建议将可管理的数据量拉入Excel，然后迭代运行查询并检查输出，以确保联接按预期执行。我不是MySQL专家，所以更新查询中可能存在语法错误。您是否在MySQL控制台中运行

SELECT

query，然后在PHP中运行

UPDATE

query？我这么说是因为有句点限定符建议跨数据库查询。在PHP中，您通常连接到一个数据库，而在服务器控制台上您可以访问所有数据库。感谢您的回答，但结果仍然相同，并且没有更新字段。我看到您正在使用字符串文字“123123”更新fa.tax_rate。该字段定义为字符串类型还是数字类型？假设您使用的是CiviCRM数据库，我认为问题在于您为fa.tax_rate指定的值超出范围。该列定义为decimal（10,8），它将值限制在-99.9999999到99.9999999之间。我试过了，但问题不是这样。我尝试了值50.55而不是123123，但仍然无法更新该字段