如何在php中以毫秒为单位获取两个日期之间的范围

如何在毫秒内获得两个日期之间的范围：

我有一个正确答案的例子：

time_start = 2018-12-18 12:33:53.1231;

time_end = 2018-12-18 12:34:10.1523;

result = 17.0292;

我想问的是，计算它的公式是什么？

我尝试了一些代码，但结果是

16.708

$dt_start = 2018-12-18 12:33:53.1231;
$dt_end = 2018-12-18 12:34:10.1523;

            $ex_start = explode(".",$dt_start);
            $ex_end = explode(".",$dt_end);
            $datetime_start = strtotime($ex_start[0]);
            $datetime_end = strtotime($ex_end[0]);
            $total_detik = $datetime_end-$datetime_start;
                // dd($ex_end[0]);
            $milis_start = floatval($ex_start[1]);
            $milis_end = floatval($ex_end[1]);
            $range_milis = $milis_start-$milis_end;
            $new_range_milis = $range_milis/10000;
                // dd($range_milis);
            $second = $datetime_end-$datetime_start+$range_milis/10000;
            dd($second);

---

//输出“16.708”

尝试此操作以查找两次之间的差异

<?php
function calculateTransactionDuration($startDate, $endDate)
{
    $startDateFormat = new DateTime($startDate);
    $EndDateFormat = new DateTime($endDate);
    $uDiff = ($startDateFormat->format('u') - $EndDateFormat->format('u')) / (1000 * 1000);;
    $diff = $startDateFormat->diff($EndDateFormat);
    $s = (int) $diff->format('%s') - $uDiff;
    $i = (int) ($diff->format('%i')) * 60; 
    $h = (int) ($diff->format('%h')) * 60 * 60; 

    return sprintf('%.6f', abs($h + $i + $s)); 
}
$time_start = '2018-12-18 12:33:53.1231';

$time_end = '2018-12-18 12:34:10.1523';

echo $difference = calculateTransactionDuration($time_start, $time_end); 
// output = 17.029200

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你应该在问题中以文本而不是图像的形式显示你的代码如果你使用的是laravel，你应该知道它使用碳元素，打开碳元素网站，搜索两个日期之间的范围。然后与msThankyou对话，了解它的工作