如何将MySQLi连接器转换为PHP-PDO
我正在阅读卢克·韦林·劳拉·汤姆森(Luke Welling Laura Thomson)的《PHP和MySQL Web开发》一书,第四版第751页,供熟悉本书的读者阅读。 然而,本书中提供的解决方案是使用MySQLIDB连接器,该连接器在测试时工作良好。我想将这个解决方案应用到我的一个使用PHPPDO连接器的项目中,但是我遇到了一个问题,因为我试图得到与教科书相同的结果。我正在寻求一些帮助,以转换MySQLi连接器来处理PDO进程。这两个示例都使用MySQL数据库。我不确定我做错了什么,也不寻求什么帮助 我试图让我的PDO过程在子id上为扩展数组生成与原始教科书数组相同的结果,以使其工作如何将MySQLi连接器转换为PHP-PDO,php,mysql,pdo,mysqli,Php,Mysql,Pdo,Mysqli,我正在阅读卢克·韦林·劳拉·汤姆森(Luke Welling Laura Thomson)的《PHP和MySQL Web开发》一书,第四版第751页,供熟悉本书的读者阅读。 然而,本书中提供的解决方案是使用MySQLIDB连接器,该连接器在测试时工作良好。我想将这个解决方案应用到我的一个使用PHPPDO连接器的项目中,但是我遇到了一个问题,因为我试图得到与教科书相同的结果。我正在寻求一些帮助,以转换MySQLi连接器来处理PDO进程。这两个示例都使用MySQL数据库。我不确定我做错了什么,也不寻
// Example taken from the text book
function expand_all(&$expanded) {
// mark all threads with children as to be shown expanded
$conn = db_connect();
$query = "select postid from header where children = 1";
$result = $conn->query($query);
$num = $result->num_rows;
for($i = 0; $i<$num; $i++) {
$this_row = $result->fetch_row();
$expanded[$this_row[0]]=true;
}
}
// The print_r form the text book example looks like this:
// result:
mysqli_result Object ( [current_field] => 0 [field_count] => 1
[lengths] => [num_rows] => 3 [type] => 0
)
// expended:
Array ( [0] => 1 ) Array ( [0] => 2 ) Array ( [0] => 4 )
//--------------------------------------------------------------//
// Know, here is my new adopted changes for using PHP PDO connector
function expand_all(&$expanded)
{
// mark all threads with children to be shown as expanded
$table_name = 'header';
$num = 1;
$sql = "SELECT postid FROM $table_name WHERE children = :num";
try
{
$_stmt = $this->_dbConn->prepare($sql);
$_stmt->bindParam(":num", $num, PDO::PARAM_INT);
$_stmt->execute();
$result = $_stmt->fetchAll(PDO::FETCH_ASSOC);
// get the $expanded children id's
foreach ($result as $key => $value)
{
foreach ($value as $k => $val)
{
$expanded[$k] = $val;
}
}
return $extended;
}
catch(PDOException $e)
{
die($this->_errorMessage = $e);
}
//close the database
$this->_dbConn = null;
}
// The print_r for the result looks like this:
Array ( [0] => Array ( [children_id] => 1 )
[1] => Array ( [children_id] => 2 )
[2] => Array ( [children_id] => 4 )
)
// The return extended print_r for the children id's
// look like this:
Array ( [children_id] => 4);
您使用的是PDO::FETCH_ASSOC,由于每个结果都有相同的列名,因此您将覆盖循环每次迭代的值
如果希望$exapnded是一个ID数组,则需要调整循环,或者应该使用PDO::FETCH_列
带回路调整:
foreach ($result as $key => $value)
{
foreach ($value as $k => $val)
{
$expanded[] = $val;
}
}
return $expanded;
$_stmt = $this->_dbConn->prepare($sql);
$_stmt->bindParam(":num", $num, PDO::PARAM_INT);
$_stmt->execute();
$result = $_stmt->fetchAll(PDO::FETCH_COLUMN, 0);
// at this point im not sure whay you are both passing
// $expanded by reference and returning it...
// if you want to overwrite this array just do $expanded = $result
// if you need to add these items TO an existing $expanded you can use
// $expanded = array_merge($expanded, $result)
带取数模式调整:
foreach ($result as $key => $value)
{
foreach ($value as $k => $val)
{
$expanded[] = $val;
}
}
return $expanded;
$_stmt = $this->_dbConn->prepare($sql);
$_stmt->bindParam(":num", $num, PDO::PARAM_INT);
$_stmt->execute();
$result = $_stmt->fetchAll(PDO::FETCH_COLUMN, 0);
// at this point im not sure whay you are both passing
// $expanded by reference and returning it...
// if you want to overwrite this array just do $expanded = $result
// if you need to add these items TO an existing $expanded you can use
// $expanded = array_merge($expanded, $result)
这两种方法都应提供如下数组:
Array(
0 => 1,
1 => 2,
2 => 4
)
那么你看到的区别是什么呢?我在这里看到了你的观点,并且是一致的,但是这个答案将生成一个数组,其中教科书示例为扩展的子id生成4个数组。那么,我怎样才能做同样的事情呢,或者是因为他们使用了for循环?