在解码的json字符串PHP中访问字段

我正在尝试使用php访问解码的json字符串中第一首歌曲的字段“id”。我尝试过所有可能的组合，比如：

$response->songs[0]->id

这是我解码的json字符串：

   Array (
[response] => Array (
[status] => Array (
[version] => 4.2
[code] => 0
[message] => Success
)
[songs] => Array (
[0] => Array (
[artist_id] => ARRH63Y1187FB47783
[id] => SOKGWES13D647BE466
[artist_name] => Kanye West
[title] => All Of The Lights
)
[1] => Array (
[artist_id] => ARRH63Y1187FB47783
[id] => SOHBKVU14509A9F6C3
[artist_name] => Kanye West
[title] => All Of The Lights
)
[2] => Array (
[artist_id] => ARRH63Y1187FB47783
[id] => SODELAY13AD1ACC8CF
[artist_name] => Kanye West
[title] => All Of The Lights
)
[3] => Array (
[artist_id] => ARRH63Y1187FB47783
[id] => SOUDIYM14B7C7B2D95
[artist_name] => Kanye West
[title] => All of the Lights
)
[4] => Array (
[artist_id] => ARRH63Y1187FB47783
[id] => SOTEMPJ13DB921F71F
[artist_name] => Kanye West
[title] => All of the Lights (
Remix
)
)
[5] => Array (
[artist_id] => ARRH63Y1187FB47783
[id] => SOXIDRL13CCFBBC829
[artist_name] => Kanye West
[title] => All Of The Lights
[LbLuke Rmx]
)
[6] => Array (
[artist_id] => ARRH63Y1187FB47783
[id] => SOTJZSO12D857905F6
[artist_name] => Kanye West
[title] => All Of The Lights (
Interlude
)
)
[7] => Array (
[artist_id] => ARVCDGF12FE08689BA
[id] => SOGLUJD130516E0D00
[artist_name] => Made famous by Kanye West
[title] => All of the lights
)
)
)
)

提前谢谢

$id = $json_array['response']['songs'][0]['id'];

解释

看看响应，您的响应是一个多维数组，这意味着您有一个由多个数组组成的数组，每个数组可以包含一个或多个数组

在您拥有的第一个数组中是“response”，这个数组包含其余的数组，因此

$id = $json_array['response']

从这个数组中，你必须在里面嵌套，直到你得到你想要的元素。它包含在另一个数组中，所以

$id = $json_array['response']['songs']

这首歌有几个元素以数字索引，因为你想要第一首歌的id，我们选择0元素

$id = $json_array['response']['songs'][0]

在此之后，您可以获得所需的元素：

$id = $json_array['response']['songs'][0]['id'];

---

json_解码返回数组，因此要访问它，请执行以下操作：

$id = $json_array['response']['songs'][0]['id'];

如果要以对象方式工作，则需要转换：

$object = (object) $json_array;
$object->response->songs[0]->id

---

json\u decode

的第二个参数的值是多少？非常感谢！！我很快就会接受你的答复。