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如何在php变量中存储ajax值?_Php_Ajax_Jquery - Fatal编程技术网

如何在php变量中存储ajax值?

如何在php变量中存储ajax值?,php,ajax,jquery,Php,Ajax,Jquery,我想在php变量中存储“选中时”的ajax值 <select name="client_name" onchange="ajaxReq('product_name', this.value);"> <option>- - -</option> <option value="SANY">SANY</option> <option value="MBFC">MBFC</option> <

我想在php变量中存储“选中时”的ajax值

 <select name="client_name" onchange="ajaxReq('product_name', this.value);">
    <option>- - -</option>
    <option value="SANY">SANY</option>
    <option value="MBFC">MBFC</option>
</select>
<span id="slo_product_name"> </span>
<span id="slo_release_no"> </span>
<script type="text/javascript">
var ar_cols = ["client_name","product_name","release_no",null]; var preid = "slo_";
</script>
如何在php变量中存储release_no的ajax值?还有别的办法吗?

function ajaxReq(col, wval) {
  removeLists(col);           
  if(wval!='- - -' && wval!='') {
      var request =  get_XmlHttp();
      var php_file = 'select_list.php';
      var  data_send = 'col='+col+'&wval='+wval;
      request.open("POST", php_file, true);
      document.getElementById(preid+col).innerHTML = 'Loadding...';   
      request.setRequestHeader("Content-type", "application/x-www-form-urlencoded");
      request.send(data_send);
      request.onreadystatechange = function() {
  if (request.readyState==4) {
      document.getElementById(preid+col).innerHTML = request.responseText; }   
          }   }    }

根据您的代码,您应该在
select\u list.php
脚本中使用此选项:

$col  = $_POST['col'];
$wval = $_POST['wval'];

// now you can use those variables to save to DB, or get some data out of DB
我假设您想要级联
元素,您应该更改
ajaxReq()
函数:

function ajaxReq(col, wval) {
    // first remove all selects that are after this one
    var remove = false;
    var next   = null; // we also need to trap next select so we can fill it
    for (i in ar_cols) {
        if (ar_cols[i] == col) {
            remove = true; // from now on, remove lists
        } else if (remove) { // if ok to remove
            if (!next) {
                next = ar_cols[i]; // now we found next column to fill
            }
            if (ar_cols[i]) { // remove only non null
                removeLists(ar_cols[i]);
            }
        }
    }      
    if(wval!='- - -' && wval!='' && next) { // also if there is column after to fill
        var request   = get_XmlHttp();
        var php_file  = 'select_list.php';
        var data_send = 'col='+col+'&wval='+wval+'&next='+next; // also add next param
        request.open("POST", php_file, true);
        document.getElementById(preid+col).innerHTML = 'Loadding...';   
        request.setRequestHeader("Content-type", "application/x-www-form-urlencoded");
        request.send(data_send);
        request.onreadystatechange = function() {
            if (request.readyState==4) {
                // we fill next select
                document.getElementById(preid+next).innerHTML = request.responseText;
            }   
        }
    }
}
您的
select\u list.php
应该如下所示:

$col  = $_POST['col']; // this is just a filter for values in next <select>
$wval = $_POST['wval'];
$next = $_POST['next']; // we need to get this param or we cannot setup next <select>

// using $col and $wval variables get values from DB

echo '<select name="' . $next . '" onchange="ajaxReq(\'' . $next . '\', this.value);">';
foreach ($data as $row) {
    echo '<option ...>...</option>'; // fix this to work for you
}
echo '</select>';
$col=$\u POST['col'];//这只是下一步中值的过滤器
$wval=$_POST['wval'];
$next=$_POST['next'];//我们需要获取此参数,否则无法设置下一个参数
//使用$col和$wval变量从数据库中获取值
回声';
foreach($行数据){
echo“…”;//解决这个问题,为您工作
}
回声';
//由于发现错误而更改代码
ajax请求应该包含一个以上的参数(
next
列),因为返回的
应该为next准备name和onchange事件,而不是当前更改的。

再次检查上面的代码。

根据您的代码,您应该在
选择列表中使用它。php
脚本:

$col  = $_POST['col'];
$wval = $_POST['wval'];

// now you can use those variables to save to DB, or get some data out of DB
我假设您想要级联
元素,您应该更改
ajaxReq()
函数:

function ajaxReq(col, wval) {
    // first remove all selects that are after this one
    var remove = false;
    var next   = null; // we also need to trap next select so we can fill it
    for (i in ar_cols) {
        if (ar_cols[i] == col) {
            remove = true; // from now on, remove lists
        } else if (remove) { // if ok to remove
            if (!next) {
                next = ar_cols[i]; // now we found next column to fill
            }
            if (ar_cols[i]) { // remove only non null
                removeLists(ar_cols[i]);
            }
        }
    }      
    if(wval!='- - -' && wval!='' && next) { // also if there is column after to fill
        var request   = get_XmlHttp();
        var php_file  = 'select_list.php';
        var data_send = 'col='+col+'&wval='+wval+'&next='+next; // also add next param
        request.open("POST", php_file, true);
        document.getElementById(preid+col).innerHTML = 'Loadding...';   
        request.setRequestHeader("Content-type", "application/x-www-form-urlencoded");
        request.send(data_send);
        request.onreadystatechange = function() {
            if (request.readyState==4) {
                // we fill next select
                document.getElementById(preid+next).innerHTML = request.responseText;
            }   
        }
    }
}
您的
select\u list.php
应该如下所示:

$col  = $_POST['col']; // this is just a filter for values in next <select>
$wval = $_POST['wval'];
$next = $_POST['next']; // we need to get this param or we cannot setup next <select>

// using $col and $wval variables get values from DB

echo '<select name="' . $next . '" onchange="ajaxReq(\'' . $next . '\', this.value);">';
foreach ($data as $row) {
    echo '<option ...>...</option>'; // fix this to work for you
}
echo '</select>';
$col=$\u POST['col'];//这只是下一步中值的过滤器
$wval=$_POST['wval'];
$next=$_POST['next'];//我们需要获取此参数,否则无法设置下一个参数
//使用$col和$wval变量从数据库中获取值
回声';
foreach($行数据){
echo“…”;//解决这个问题,为您工作
}
回声';
//由于发现错误而更改代码
ajax请求应该包含一个以上的参数(
next
列),因为返回的
应该为next准备name和onchange事件,而不是当前更改的。

再次检查上面的代码。

您的ajax函数在哪里?我们可以看到
ajaxReq
函数
PHP脚本
服务器端运行
并且
ajax
客户端运行
PHP变量
,因此您不能将
ajax
值分配给
PHP变量
,是的,您可以在
Ajax调用之后
操作DOM
。您正在发送
'col='+col+'&wval='+wval到您的PHP脚本。索引
release\u no
根本没有通过。您的ajax函数在哪里?我们可以看到
ajaxReq
函数
PHP脚本
服务器端运行
并且
ajax
客户端运行
因此您不能将
ajax
值分配给
PHP变量
,是的,您可以在
Ajax调用之后
操作DOM
。您正在发送
'col='+col+'&wval='+wval到您的PHP脚本。索引
release\u no
根本没有通过。