Php 如何将现有数据与新数据合并?
方法1:在这里,我编写了将预订座位数据插入数据库的代码 问题:当我预订新座位时,它将创建新行,所以我得到了重复的行,所以我尝试了方法2 方法1代码:Php 如何将现有数据与新数据合并?,php,laravel,Php,Laravel,方法1:在这里,我编写了将预订座位数据插入数据库的代码 问题:当我预订新座位时,它将创建新行,所以我得到了重复的行,所以我尝试了方法2 方法1代码: $booking = new Bookings(); $booking->users_id = 4; $booking->schedules_id = $schedules_id; $booking->buses_id = $buses_id; $booking-&g
$booking = new Bookings();
$booking->users_id = 4;
$booking->schedules_id = $schedules_id;
$booking->buses_id = $buses_id;
$booking->routes_id = $routes_id;
$booking->seat = implode(',', $seat);
$booking->price = $request->price;
$booking->profile = 'pending';
方法2:此处检查计划id
是否等于存在计划id
,然后更新座位和其他数据
问题:插入新数据更新旧数据
方法2代码:
$booking = Bookings::updateOrCreate(
['schedules_id' => $schedules_id], // match the row based on this array
[ // update this columns
'buses_id' => $buses_id,
'routes_id' => $routes_id,
'seat' => json_encode($seat),
'price' => $request->price,
'profile' => 'pending',
]
);
//我不知道这在逻辑上是正确的还是错误的
我的想法:这里我检索旧数据并存储到一个变量中,然后将旧数据和新数据合并到一列中
问题:获取错误
我的想法代码:
$extSeat = DB::table('bookings')->select('seat')->get();
$booking = Bookings::updateOrCreate(
['schedules_id' => $schedules_id],
[ // update this columns
'buses_id' => $buses_id,
'routes_id' => $routes_id,
'seat' => implode(",", array_merge($seat,$extSeat)),
'price' => $request->price,
'profile' => 'pending',
]);
我到底需要什么我需要在不更新的情况下将现有数据与新数据合并
旧数据看起来像A1、B1
插入新数据时,如
C1
我需要这样的数据
A1、B1、C1
我希望我解释得足够清楚。非常感谢您的帮助。我不知道这是否是正确的逻辑,但对我来说很有效,欢迎您提出任何其他建议
$extSeat = DB::table('bookings')->select('seat')->first();
$extSeat = explode(",", $extSeat->seat);
$booking = Bookings::updateOrCreate(
['schedules_id' => $schedules_id],
[ // update this columns
'buses_id' => $buses_id,
'routes_id' => $routes_id,
'seat' => implode(",", array_merge($seat,$extSeat )),
'price' => $request->price,
'profile' => 'pending',
]);
为什么不在座位区使用关系?@stUrb先生,你能解释清楚吗?