Php 获取两个不同表中两列的差异?

Php 获取两个不同表中两列的差异?,php,mysql,sql,mysqli,Php,Mysql,Sql,Mysqli,我的sql代码执行,但我不知道如何获得采购请求总数量和采购订单数量的差异 表采购订单 counter | qty | --------------- 100001 | 10 | 100001 | 10 | 100001 | 10 | 100004 | 30 | 表购买请求 counter | total_qty | --------------------- 100001 | 50 | 100002 |

我的sql代码执行,但我不知道如何获得采购请求总数量和采购订单数量的差异

表采购订单

counter | qty |      
---------------         
100001  | 10  |  
100001  | 10  |  
100001  | 10  |  
100004  | 30  |  
表购买请求

counter | total_qty |
---------------------
100001  |     50    |  
100002  |     100   |  
100003  |     50    |  
100004  |     70    | 
我想像这样编码,但我不知道如何在我的代码中混合它

a.total_qty-b.qty as balance 
这是我的密码

<?php
    $mysqli = new mysqli("localhost", "root", "", "test");

        $result = $mysqli->query("
        select a.counter,a.total_qty from purchase_request a inner join purchase_order b on a.counter= b.counter group by a.counter
        ");
        echo'<table id="tfhover" cellspacing="0" class="tablesorter" style="text-transform:uppercase;" border="1px">
            <thead>
            <tr>
            <th></th>
        <th>counter</th>
        <th>QTY</th>
        <th>balance</th>
            </tr>
            </thead>';
            echo'<tbody>';
        $i=1;   
    while($row = $result->fetch_assoc()){
        echo'<tr>
                <td>'.$i++.'</td>
                <td>'.$row['counter'].'</td>
                <td>'.$row['total_qty'].'</td>
                <td>'.$row['balance'].'</td>
            </tr>';
           }
        echo "</tbody></table>";

    ?>

你试过这个吗

    select a.counter,
           a.total_qty,
           a.total_qty - b.qty balance 
      from (select counter,
                   sum(total_qty) total_qty
              form purchase_request
          group by counter) a 
inner join (select counter,
                   sum(qty) qty
              from purchase_order 
          group by counter) b 
        on a.counter= b.counter 
  group by a.counter

编辑:我知道了,你需要的是把你的数量加起来,然后做数学运算

它是有效的,但余额是40,我需要得到3 100001个数量计数器和减去总数量的总和。我应该得到20,因为余额情况越来越糟,$row['total\u qty']丢失了,100001的余额变成了120:/I得到了,我更改了,a.total\u qty,a.total\u qty-总和(b.qty)余额。只有一件事,为什么它在没有(as)的情况下工作?对不起,我是sqlI新手我再次更改了查询,我想这应该是您正在查找的致命错误:对非对象调用成员函数fetch_assoc()。计数器100001 balance=120是错误的,但计数器100004=40是正确的。为什么呢?但这是我的答案a.total_qty-总和(b.qty)作为余额,两个计数器=都是正确的。如果正确?当有多行具有相同计数器时,这将在采购订单和采购请求之间提供笛卡尔连接
    select a.counter,
           a.total_qty,
           sum(a.total_qty) - sum(b.qty) as balance 
      from purchase_request a 
left inner join purchase_order b 
        on a.counter= b.counter 
  group by a.counter