Php 注销按钮将uesr重定向到同一页面，而不是注销用户

php是主页面。当用户转到SheetTime.php时，他们被重定向到Login.php；如果他们在那里登录成功，他们将被引导到SheetTime.php的实际内容

问题在于我的注销按钮。当用户单击注销按钮时，他们总是被重定向到SheetTime.php（页面看起来只是刷新），而不是实际注销并返回Login.php。我尝试将Logout.php中的位置更改为Login.php并检查了URL，但得到了相同的结果

我的理论是，由于我将Logout.php中的位置设置为SheetTime.php，它会返回Login.php，然后返回SheetTime.php，等等。这里似乎陷入了一个循环，我对此类循环没有太多经验

当用户单击注销按钮时，我希望他们注销站点并返回登录页面，以便他们可以再次登录站点。有什么建议吗？或者你认为我的代码有什么问题吗

---

Logout.php：

<?php
session_start();
unset($_SESSION["STYLE"]);
header("Location: SheetTime.php");
?>

<?php
     session_start();
     session_unset();
    header("Location: index.php");
?>

---

首先，对于真正的注销，我建议执行然后重定向。它将终止会话。您的会话应进行如下测试：

if(isset($_SESSION["STYLE"]))
{
   //Do Coding magic
}
else
{
   //Redirect to login page
}

index.php

<?php
//Test for valid login
session_start();
if(isset($_SESSION["STYLE"]))
{
    echo "<a href='logout.php'>Logout</a>";

}
else
{
    echo "<a href='login.php'>Login</a>";
}


?>

login.php：

<?php
session_start();
$_SESSION["STYLE"]="VALIDLOGIN";
 header("Location: index.php");
?>

logout.php：

<?php
session_start();
unset($_SESSION["STYLE"]);
header("Location: SheetTime.php");
?>

<?php
     session_start();
     session_unset();
    header("Location: index.php");
?>

更新的电子表格.php：

<?php  
session_start(); 
//----------- Check if any user is currently logged in ---------------
if (!isset($_SESSION['STYLE'])) 
{
   echo "You are not logged in!<br>";
   echo "<a href='login.php'>Logout</a>";
}
else
{
    echo "You are logged in!<br>";
    echo "<a href='logout.php'>Logout</a>";
}
?>

---

希望这有帮助

EntiendNull抓住了要点：Login.php包含SheetTime.php的头

---

您需要在此位置标题之前添加一个条件，以便仅在用户已登录时重定向。

我想您在此代码之前有一个表

<br /><form action='Logout.php' method='post'>
    <input value='Log out' id='Submit' type='submit' /></td>               
</form>

换成这个,

<br /><form action='Logout.php' method='post'>
    <input value='Log out' id='Submit' type='submit' />
</form>
</td>               

---

顺便说一下，如果是一个url，为什么不使用

Logout.php

<?php
session_start();
unset($_SESSION['style']); //unset will work fine for a specifik session variable. If you want to get rid of all **your** active sessions for your domain use session_destroy();
session_destroy();
header("Location: Login.php");
exit;
?>

<?php  
session_start(); 
if(!isset($_SESSION['style']) || $_SESSION['style'] == '')){
     header("Location: http://www.websitetotestfortest.edu/theTimePro/Login.php");
     exit;
     }

//There's a valid session, so do things here.

<?php
session_start();
if(isset($_POST['doLogin'])){
    $db = new PDO("..."); //your database details
    $statement = $db->prepare("SELECT id FROM your_user_table WHERE username = :username AND password = :password");

    $statement->execute(array(':username' => $_POST['userName'], ':password' => $_POST['passwd']));
    $count = $statement->rowCount();

    if($count <= 0){
        header("Location: login.php?error"); //go here if there's an error... receive  it with if(isset($_GET['error'])){ echo 'your text';}    
        exit;
        }

       $row = $statement->fetch(); // if a result was found, fetchit
       $_SESSION['style'] = 'yourValue'; // define the session variable
       header("Location: Path-To-SheetTime.php");
       exit;
       }
?>

<form method="post" action="login.php">
    <!-- your login form -->
    <input type="text" name="userName"/>
    <br/>
    <input type="password" name="passwd"/>
     <br/>
    <input type="submit" name="doLogin" value="Login"/>
</form>

SheetTime.php

<?php
session_start();
unset($_SESSION['style']); //unset will work fine for a specifik session variable. If you want to get rid of all **your** active sessions for your domain use session_destroy();
session_destroy();
header("Location: Login.php");
exit;
?>

<?php  
session_start(); 
if(!isset($_SESSION['style']) || $_SESSION['style'] == '')){
     header("Location: http://www.websitetotestfortest.edu/theTimePro/Login.php");
     exit;
     }

//There's a valid session, so do things here.

<?php
session_start();
if(isset($_POST['doLogin'])){
    $db = new PDO("..."); //your database details
    $statement = $db->prepare("SELECT id FROM your_user_table WHERE username = :username AND password = :password");

    $statement->execute(array(':username' => $_POST['userName'], ':password' => $_POST['passwd']));
    $count = $statement->rowCount();

    if($count <= 0){
        header("Location: login.php?error"); //go here if there's an error... receive  it with if(isset($_GET['error'])){ echo 'your text';}    
        exit;
        }

       $row = $statement->fetch(); // if a result was found, fetchit
       $_SESSION['style'] = 'yourValue'; // define the session variable
       header("Location: Path-To-SheetTime.php");
       exit;
       }
?>

<form method="post" action="login.php">
    <!-- your login form -->
    <input type="text" name="userName"/>
    <br/>
    <input type="password" name="passwd"/>
     <br/>
    <input type="submit" name="doLogin" value="Login"/>
</form>

---

好吧。。您将用户发送到Login.php，在Login.php中，您将用户发送到SheetTime.php。另外，请尝试在第1行将if更改为if（！isset（$user\u name）&&&$user\u name！=''）

这一个缺少a）这不起作用：请参阅我更新的示例…我在本地运行了它。如果您需要更多帮助，请告诉我。您的示例和建议非常有用：）但是我忘了提到一些重要的事情，用户的凭据已（成功）从数据库中提取。现在的做法是什么？我也尝试了你为Logout.php发布的内容，但没有成功。谢谢你的时间