Php mysql从两个表中选择一个值
我有两张桌子:Php mysql从两个表中选择一个值,php,mysql,sql,Php,Mysql,Sql,我有两张桌子: users user_id | user_name | user_avatar 及 我需要一个查询,将选择一个数组中的所有化身,然后,我想回显它们,作为一个照片库 有人能帮我吗 我试过了 SELECT e.event_avatar , u.user_avatar as img FROM events e ,users u ORDER BY e.id DESC LIMIT 0, 17" 对于SQL位,您似乎想要一个联合: Select event_avatar From
users
user_id | user_name | user_avatar
及
我需要一个查询,将选择一个数组中的所有化身,然后,我想回显它们,作为一个照片库
有人能帮我吗
我试过了
SELECT e.event_avatar , u.user_avatar as img FROM events e ,users u ORDER BY e.id DESC LIMIT 0, 17"
对于SQL位,您似乎想要一个联合:
Select
event_avatar
From
events
Union All
Select
user_avatar
From
users
对于SQL位,您似乎想要一个联合:
Select
event_avatar
From
events
Union All
Select
user_avatar
From
users
您的查询有什么问题?
Array([0]=>Array([0]=>image1.jpg[event\u cover]=>image.jpg[1]=>Picture 7\u 1349112449.png[img]=>Picture 7\u 1349112449.png)[1]=>Array([0]=>image.jpg[event\u main\u cover\u id]=>image.jpg[1]=>[img]=>)
您的查询有什么问题?Array([0]=>Array([0]=>image1.jpg[event\u cover]=>image.jpg[1]=>Picture 7_1349112449.png[img]=>Picture 7_1349112449.png)[1]=>Array([0]=>image.jpg[event\u main\u cover\u id]=>image.jpg[1]=>[img]=>)