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Php PDO多个命名占位符无法检索数据_Php_Mysql_Pdo - Fatal编程技术网

Php PDO多个命名占位符无法检索数据

Php PDO多个命名占位符无法检索数据,php,mysql,pdo,Php,Mysql,Pdo,如果准备好的语句只有一个指定的占位符,那么到目前为止我编写的代码可以正常工作,但是如果查询有多个条件,它不会从数据库返回任何结果 例如: $query = array(); $query['columns'] = array('*'); $query['tables'] = array('esl_comments'); $query['where'] = array( 'esl_comments.commentVisible' => array('=', 'Y') ); 很好。但

如果准备好的语句只有一个指定的占位符,那么到目前为止我编写的代码可以正常工作,但是如果查询有多个条件,它不会从数据库返回任何结果

例如:

$query = array();
$query['columns'] = array('*');
$query['tables'] = array('esl_comments');
$query['where'] = array(
    'esl_comments.commentVisible' => array('=', 'Y')
);
很好。但如果我尝试:

$query = array();
$query['columns'] = array('*');
$query['tables'] = array('esl_comments');
$query['where'] = array(
    'esl_comments.commentVisible' => array('=', 'Y'),
    'esl_comments.commentID' => array('=', '1'),
);
(注意附加的commentID参数)尽管mySQL数据库中存在满足条件的数据,但它无法返回任何内容

我编写的PDO代码是:

$sql ='SELECT ';
                foreach($query['columns'] as $column){ //What columnns do we want to fetch?
                    $sql.=$column . ", ";
                }
                $sql = rtrim($sql, " ,");
                $sql .=' FROM '; //Which tables will we be accessing?
                foreach($query['tables'] as $tables){
                    $sql.=$tables . ", ";
                }
                $sql = rtrim($sql, " ,"); //Get rid of the last comma
                $sql .=' WHERE ';

                if(array_key_exists('where', $query)) //check if a where clause was provided
                {
                    $fieldnames = array_keys($query['where']);
                    $count = 0;
                    $size = sizeof($fieldnames);
                    $bindings = array();
                    foreach($query['where'] as $where){

                        $cleanPlaceholder = str_replace("_", "", $fieldnames[$count]);
                        $cleanPlaceholder = str_replace(".", "", $cleanPlaceholder);
                        $sql.=$fieldnames[$count].$where[0].":".$cleanPlaceholder." AND ";
                        $bindings[$cleanPlaceholder]=$where[1];
                        $count++;
                    }
                    $sql = substr($sql, 0, -5);  //Remove the last AND
                }
                else{ //no where clause so set it to an always true check
                    $sql.='1=1';
                    $bindings=array('1'=>'1'); //Provide default bindings for the statement
                }

                $sql .= ';'; //Add the semi-colon to note the end of the query
                echo $sql . "<br/><br/>";
            //  exit();
                $stmt = $this->_connection->prepare($sql);

                foreach($bindings as $placeholder=>$bound){
                    echo $placeholder . " - " . $bound."<br/>";
                    $stmt->bindParam($placeholder, $bound);
                }

                $result = $stmt->execute();
                echo $stmt->rowCount() . " records<br/>";

                $results = $stmt->fetchAll(PDO::FETCH_ASSOC);
被绑定的参数如下所示:

SELECT * FROM esl_comments WHERE esl_comments.commentVisible=:eslcommentscommentVisible AND esl_comments.commentID=:eslcommentscommentID;
eslcommentscommentVisible - Y
eslcommentscommentID - 1
bindParam需要一个引用 这个问题是由在foreach循环中绑定参数的方式引起的

foreach($bindings as $placeholder=>$bound){
    echo $placeholder . " - " . $bound."<br/>";
    $stmt->bindParam($placeholder, $bound);
}
传递值 使用
bindValue
代替
bindParam

foreach($bindings as $placeholder => $bound) {  
    $stmt->bindValue($placeholder, $bound);     // bind the value to the statement
}
bindParam需要一个引用 这个问题是由在foreach循环中绑定参数的方式引起的

foreach($bindings as $placeholder=>$bound){
    echo $placeholder . " - " . $bound."<br/>";
    $stmt->bindParam($placeholder, $bound);
}
传递值 使用
bindValue
代替
bindParam

foreach($bindings as $placeholder => $bound) {  
    $stmt->bindValue($placeholder, $bound);     // bind the value to the statement
}

显示有效查询和无效查询的最终SQL字符串。如果没有,也显示错误消息。显示有效和无效查询的最终SQL字符串。当错误消息不存在时,也显示错误消息。太好了!我没有意识到bindValue()和bindParam()之间的区别。这为我解决了问题。非常感谢,太好了!我没有意识到bindValue()和bindParam()之间的区别。这为我解决了问题。非常感谢你。