Php 错误的布尔值语句未插入数据库
我有一个JSON数组,如下所示:Php 错误的布尔值语句未插入数据库,php,mysql,prepared-statement,Php,Mysql,Prepared Statement,我有一个JSON数组,如下所示: { "operation": "update_original_team_member", "teamMember": { "teamMemberPresent": false, "unique_id": "5a5b7f6b835408.50059003", "user_unique_id": "59bea8b7d56a63.33388595" } } 我试图将其插入mySQL数据库,但每
{
"operation": "update_original_team_member",
"teamMember": {
"teamMemberPresent": false,
"unique_id": "5a5b7f6b835408.50059003",
"user_unique_id": "59bea8b7d56a63.33388595"
}
}
我试图将其插入mySQL数据库,但每次都失败了,但当我将false改为true时,它就成功了,你知道为什么吗
要插入的表格如下所示:
CREATE TABLE team_member (
team_member_id int(11) NOT NULL AUTO_INCREMENT,
unique_id varchar(23) NOT NULL,
fullName varchar(50) NOT NULL,
user_unique_id varchar(23) NOT NULL,
present boolean NOT NULL,
date_last_present datetime DEFAULT NULL,
points int(50) NULL,
team_id int (11) NOT NULL,
PRIMARY KEY (team_member_id),
FOREIGN KEY (`team_id`)
REFERENCES `ocidb_CB9s149919`.`team` (`team_id`)
);
JSON数组是从Reformation(Reformation是Android的REST客户端)发送的,接收方式如下:
if ($operation == 'update_original_team_member') {
if (isset($data -> teamMember) && !empty($data -> teamMember)&& isset($data -> teamMember -> teamMemberPresent)
&& isset($data -> teamMember -> unique_id)&& isset($data -> teamMember -> user_unique_id)){
$teamMember = $data -> teamMember;
$teamMemberPresent = $teamMember -> teamMemberPresent;
$unique_id = $teamMember -> unique_id;
$user_unique_id = $teamMember -> user_unique_id;
echo $fun -> updatePresent($teamMemberPresent,$unique_id, $user_unique_id);
} else {
echo $fun -> getMsgInvalidParam();
}
此操作已通过以下功能:
public function updatePresent($teamMemberPresent,$unique_id, $user_unique_id){
$db = $this -> db;
if (!empty ($teamMemberPresent)&& !empty ($unique_id)&& !empty ($user_unique_id)){
$result = $db -> updatePresent($teamMemberPresent,$unique_id, $user_unique_id);
if ($result) {
$response["result"] = "success";
$response["message"] = "Active Students Have Been Recorded!";
return json_encode($response);
} else {
$response["result"] = "failure";
$response["message"] = "Unable To Update Details, Please Try Again";
return json_encode($response);
}
} else {
return $this -> getMsgParamNotEmpty();
}
}
我用于更新的查询是:
public function updatePresent($teamMemberPresent,$unique_id, $user_unique_id){
$sql = "UPDATE team_member SET present = :present WHERE unique_id = :unique_id AND user_unique_id = :user_unique_id";
// Prepare statement
$query = $this ->conn ->prepare($sql);
// execute the query
$query->execute(array(':present' => $teamMemberPresent,':unique_id' => $unique_id, ':user_unique_id' => $user_unique_id));
if ($query) {
return true;
} else {
return false;
}
}
我使用postman尝试隔离问题,并将其缩小为$teamMemberPresent
变量failing,指出当它作为false相互关联时它是空的,但我不知道为什么。如前所述,当其设置为true时,查询工作正常
任何指导都将不胜感激 将布尔变量强制转换为int
$query->execute(array(':present' => (int) $teamMemberPresent,':unique_id' => $unique_id, ':user_unique_id' => $user_unique_id));
// this one -> (int) $teamMemberPresent
在
updatePresent()
函数中,此代码无法识别数据是否有效,并跳过数据库更新:
if (!empty ($teamMemberPresent)&& !empty ($unique_id)&& !empty ($user_unique_id)){
...
原因是empty($teamMemberPresent)
如果其参数具有false
值,则返回true
说:
如果变量不存在或其值等于FALSE,则认为该变量为空
您应该使用isset($teamMemberPresent)
下面是一个演示:
if (isset($data -> teamMember)
&& !empty($data -> teamMember)
&& isset($data -> teamMember -> teamMemberPresent)
&& isset($data -> teamMember -> unique_id)
&& isset($data -> teamMember -> user_unique_id))
{
echo "Should all be OK\n";
$teamMember = $data -> teamMember;
$teamMemberPresent = $teamMember -> teamMemberPresent;
if (!empty($teamMemberPresent)) {
echo "Confirmed, not empty\n";
} else {
echo "Woops! It's empty\n";
}
}
输出:
Should all be OK
Woops! It's empty
调用函数时,
$teamMemberPresent
在函数中的值是什么?如何调用updatePresent
,以及向其传递什么值?如果没有这些信息,你的问题就无法回答。这些值都在JSON数组中(在我问题的开头),我刚刚在你建议的部分添加了isset
,它解决了我的问题!我认为,因为在传递到函数updatePresent之前,我检查了isset
,所以没有必要再次检查它,但显然是这样。谢谢你的建议,我现在就接受你的答复。