Warning: file_get_contents(/data/phpspider/zhask/data//catemap/1/php/256.json): failed to open stream: No such file or directory in /data/phpspider/zhask/libs/function.php on line 167

Warning: Invalid argument supplied for foreach() in /data/phpspider/zhask/libs/tag.function.php on line 1116

Notice: Undefined index: in /data/phpspider/zhask/libs/function.php on line 180

Warning: array_chunk() expects parameter 1 to be array, null given in /data/phpspider/zhask/libs/function.php on line 181

Warning: file_get_contents(/data/phpspider/zhask/data//catemap/2/jquery/86.json): failed to open stream: No such file or directory in /data/phpspider/zhask/libs/function.php on line 167

Warning: Invalid argument supplied for foreach() in /data/phpspider/zhask/libs/tag.function.php on line 1116

Notice: Undefined index: in /data/phpspider/zhask/libs/function.php on line 180

Warning: array_chunk() expects parameter 1 to be array, null given in /data/phpspider/zhask/libs/function.php on line 181
php复选框如果未选中则插入0_Php_Jquery_Html - Fatal编程技术网

php复选框如果未选中则插入0

php复选框如果未选中则插入0,php,jquery,html,Php,Jquery,Html,我在PHP中有一个复选框,如果数据库中的复选框的值为1,我想检查它,如果保存且未选中,则在数据库中插入“0” 示例复选框 <input type="checkbox" name="chckpagibigcon" <?php if(isset($_POST['chckpagibigcon'])){ echo 'checked value = "0"'; }else{ e

我在PHP中有一个复选框,如果数据库中的复选框的值为1,我想检查它,如果保存且未选中,则在数据库中插入“0”

示例复选框

  <input type="checkbox" name="chckpagibigcon" <?php 
            if(isset($_POST['chckpagibigcon'])){
                echo 'checked value = "0"';
            }else{
                echo 'value = "1"';
            }
            ?>>

试试这个:

<input type="checkbox" name="chckpagibigcon" <?php 
                                if(isset($_POST['chckpagibigcon'])){
                                    echo 'checked value = "1"';
                                }else{
                                    echo 'value = "0"';
                                }
                                ?>>

相当好的解决方案是:

<input type='hidden' name='chckpagibigcon' value='0'/>
<input type='checkbox' name='chckpagibigcon' value='1' <?php echo (isset($_POST['chckpagibigcon']))?'checked':'';?>/>


更改
echo'checked value=“0”
回显“value=“0”:)这将为您提供信息。不要忘记,您需要一个带有表单的提交按钮来正确传递post变量