如何在Powershell中创建只接受字符串和变量的函数？
我想在Powershell中运行一个名为Get-OSArchitecture的函数，该函数告诉我当您给计算机一个域名时，它是32位系统还是64位系统。但是，它只接受诸如“SALES-DENNY”之类的字符串，而不接受带有诸如$string1之类的存储字符串的变量。我曾经尝试过一种叫做Out String的东西，但是这个函数在获取字符串时非常顽固，与变量无关 以下代码用于获取全局Get-OSArchitecture函数：如何在Powershell中创建只接受字符串和变量的函数？,powershell,Powershell,我想在Powershell中运行一个名为Get-OSArchitecture的函数，该函数告诉我当您给计算机一个域名时，它是32位系统还是64位系统。但是，它只接受诸如“SALES-DENNY”之类的字符串，而不接受带有诸如$string1之类的存储字符串的变量。我曾经尝试过一种叫做Out String的东西，但是这个函数在获取字符串时非常顽固，与变量无关 以下代码用于获取全局Get-OSArchitecture函数： function global:Get-OSArchitecture {
function global:Get-OSArchitecture {
#Requires -Version 2.0
[CmdletBinding()]
Param
(
[Parameter(Mandatory=$false,
Position=1,
ValueFromPipeline=$true,
ValueFromPipelineByPropertyName=$true)]
[String[]]$ComputerName = $env:COMPUTERNAME
)#End Param
Begin
{
Write-Verbose "Retrieving Computer Info . . ."
}
Process
{
$ComputerName | foreach {
$ErrorActionPreference = 0
$Computer = $_
$Windir,$OSArchitecture,$OSVersion = Get-WmiObject -class Win32_OperatingSystem -ComputerName $_ |
foreach {$_.WindowsDirectory,$_.OSArchitecture,$_.Version}
$SysDrive = ($Windir -split ":")[0] + "$"
# $OSVersion[0]
# $OSArchitecture is only suppored on OSVersion -ge 6
# I was going to test for that, however now I just test if $OSArchitecture -eq $True
Write-Verbose "Operating System version on $Computer is: $OSVersion"
if ($OSArchitecture)
{
New-Object PSObject -Property @{
Hostname=$Computer
OSArchitecture=$OSArchitecture
SysDrive=$SysDrive
OSVersion=$OSVersion
WinDir=$WinDir
}
}
else
{
# check the program files directory
write-verbose "System Drive on $Computer is: $SysDrive"
$x64 = "\\$Computer\" + $SysDrive + "\Program Files (x86)"
if (test-path ("\\$Computer\" + $SysDrive))
{
if (test-path $x64)
{
New-Object PSObject -Property @{
Hostname=$Computer
OSArchitecture="64-bit"
SysDrive=$SysDrive
OSVersion=$OSVersion
WinDir=$WinDir
}
}
elseif (!(test-path $x64))
{
New-Object PSObject -Property @{
Hostname=$Computer
OSArchitecture="32-bit"
SysDrive=$SysDrive
OSVersion=$OSVersion
WinDir=$WinDir
}
}
}
else {"Something wrong determining the System Drive"}
}
} | select Hostname,OSArchitecture,SysDrive,WinDir,OSVersion
}#Process
End
{
}#End
}#Get-OSArchitecture
$string1 = "SALES-DENNY"
Get-OSArchitecture $string1
Get-OSArchitecture "SALES-DENNY"
我希望函数能给出名为“SALES-DENNY”的计算机的正确体系结构，但如果我不将其作为字符串输入，我总是得到一个空白结果。尽管将计算机名作为硬编码字符串或变量中的名称或IP输入并不重要，我相信您可以通过不测试
程序文件（x86）相反，您可以依赖另外两个WMI函数来获取操作系统的“比特度”：
function Get-OSArchitecture {
[CmdletBinding()]
param(
[Parameter(Mandatory=$false, ValueFromPipeline=$true, ValueFromPipelineByPropertyName=$true, Position=0)]
[string[]]$ComputerName = $env:COMPUTERNAME
)
process {
foreach ($computer in $ComputerName) {
Write-Verbose "Retrieving info for computer '$computer'"
$info = Get-WmiObject -Class Win32_OperatingSystem -ComputerName $computer |
Select-Object @{Name = 'HostName'; Expression = { $_.PSComputerName}},
OSArchitecture,
@{Name = 'SysDrive'; Expression = { '{0}$' -f ($_.SystemDrive).Substring(0,1) }},
@{Name = 'WinDir'; Expression = { $_.WindowsDirectory}},
@{Name = 'OSVersion'; Expression = { $_.Version }}
if ($info.OSArchitecture) {
$info.OSArchitecture = '{0}-bit' -f ($info.OSArchitecture -replace '\D+','')
}
else {
$info.OSArchitecture = '{0}-bit' -f (Get-WmiObject -Class Win32_Processor -ComputerName $computer).AddressWidth
# or do:
# $info.OSArchitecture = '{0}-bit' -f (((Get-WmiObject -Class Win32_ComputerSystem -ComputerName $computer).SystemType -replace '\D+', '') -replace '86', '32')
}
# emit info
$info
}
}
}
希望这有帮助传递字符串文字和包含字符串的变量之间应该没有区别。您的问题中没有足够的信息来诊断问题。请考虑提供一个。如果你说它失败了，它是怎么失败的？你有什么错误？另外，请确保你的代码样本足够小，它仍然可以重现这个问题。奇怪的是，它对我有效。我将上面的代码保存在get-osarchitecture.ps1中，然后输入
\获取osarchitecture