Python 2.7 需要将\u mobile的no\u转换为整数格式 需要将“no_of_mobile”变量转换为整数格式，并使用循环打印

在这里， 如果您还需要品牌名称，那么应该修改解析html文件的代码并相应地打印

import requests
import re
from bs4 import BeautifulSoup

request =  requests.get("https://priceraja.com/mobile/brands/").text
soup = BeautifulSoup(request,"html.parser")
mspec = soup.find('ul', attrs = {"class","top-brands"})
list=[]
no_of_mob=[] ## Note the change in list name
for link in mspec.find_all('li'):
    li=link.getText('li')
    lit =str(li).split("\n")
    litt=lit
    no_of_mobile= litt[1].replace('(', '').replace(')', '')
    no_of_mob.append(int(no_of_mobile)) ## appending the values to the list, here type of the object is string.
no_of_mob=sorted(set(no_of_mob), key=lambda x:int(x),reverse=True) ## sorting the converted integer values
print no_of_mob[:5] ## printing top 5 (Highest no of mobiles)

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你能回答你的问题吗？这真的不清楚。需要将所有的no_of_mobile转换为整数格式，并使用loop只打印几个top integer。你能用这些信息回答你的问题吗？评论是给我们的：）@nishantkumar好吧。。通过单击答案中的勾号接受答案

import requests
import re
from bs4 import BeautifulSoup

request =  requests.get("https://priceraja.com/mobile/brands/").text
soup = BeautifulSoup(request,"html.parser")
mspec = soup.find('ul', attrs = {"class","top-brands"})
list=[]
no_of_mob=[] ## Note the change in list name
for link in mspec.find_all('li'):
    li=link.getText('li')
    lit =str(li).split("\n")
    litt=lit
    no_of_mobile= litt[1].replace('(', '').replace(')', '')
    no_of_mob.append(int(no_of_mobile)) ## appending the values to the list, here type of the object is string.
no_of_mob=sorted(set(no_of_mob), key=lambda x:int(x),reverse=True) ## sorting the converted integer values
print no_of_mob[:5] ## printing top 5 (Highest no of mobiles)