Python 3.x Python：将变量从循环中取出

我有以下代码：

for response_i in response['response']:

  var_1=None
  if response_i['objkey'] == 'explorecube_data':
      var_1=response_i['objcontent'][0]['title']
  if response_i['objkey'] == 'explorecube_data' and response_i['objcontent'][0]['title'] == var_1:
    print(var_1)

  dim_1=None
  if response_i['objkey'] == 'explorecube_dimvalues':
      dim_1=response_i['objcontent'][0]['title']
  if response_i['objkey'] == 'explorecube_dimvalues' and response_i['objcontent'][0]['title'] == dim_1:
      print(dim_1)

  ab=[var_1, dim_1]
  print(ab)

我更新了问题。 输出结果如下：

['tos', None]
[None, None]
[None, 'lat']
[None, None]

我希望得到以下输出：

['tos', 'lat']

---

我很欣赏任何解决此问题的建议

尝试类似的方法，将数据转换为pandas dataframe并删除None值

import pandas as pd


data = []

data.append([var_1, dim_1])

df = pd.DataFrame(data, columns=['var_1', 'dim_1'])
df = df.dropna(how = 'all')

---

使用生成器生成所需的结果，然后打印

def PrintGen():
    for response_i in response['response']:
        if response_i['objkey'] == 'explorecube_data' or response_i['objkey'] == 'explorecube_dimvalues':
            yield response_i['objcontent'][0]['title']
ab =PrintGen()
listab =list(ab)
print(listab)

---

生成器用于生成满足需求的对象，它们适合您。

您可以简单地将值附加到

ab

，当值不是

None

时。然后您需要在循环外部实例化并打印

ab

ab = []
for response_i in response['response']:
  var_1=None
  if response_i['objkey'] == 'explorecube_data':
      var_1=response_i['objcontent'][0]['title']
  if response_i['objkey'] == 'explorecube_data' and response_i['objcontent'][0]['title'] == var_1:
    print(var_1)
    ab.append(var1)

  dim_1=None
  if response_i['objkey'] == 'explorecube_dimvalues':
      dim_1=response_i['objcontent'][0]['title']
  if response_i['objkey'] == 'explorecube_dimvalues' and response_i['objcontent'][0]['title'] == dim_1:
      print(dim_1)
      ab.append(dim1)

print(ab)

---

response['response']

包含什么？使用复制和粘贴输入代码以确保缩进与您编写的缩进相同。您的原件。问题已更新。请删除

var_1=None

和

dim_1=None

，然后将

print（ab）

移出循环。我将ab=[var_1，dim_1]，print（ab）移出循环