在python中转换为列表的矩阵

有一个具有Wolfram Mathematica矩阵样式的txt文件（可以是1000多个字符串）：

我需要从中创建嵌套列表，以便在python中进行进一步计算。 结果应该是——

s=[[[0.00036], [1], [0], [1], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0]],[[0.0003],.. and so on

---

我是python新手，你能帮我吗

这里有一些代码，可以让换行符出现在您喜欢的任何地方。但是条目只能是浮点数

from ast import literal_eval
with open('filename') as f:
    lis = [[[abs(literal_eval(item))] for item in 
                     line.rstrip('},\n').lstrip('{').split(', ')] for line in f]
    print lis
...     
[[[0.00036], [1], [0], [1], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0]], [[0.0003], [1.00026], [2], [0], [1], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0]], [[0], [0.0002], [2], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0]]]

f = open("filename", "r")

buff = ""
array = []
for line in f:
    buff += line
    if "}" in line:
        start = buff.index("{")
        end = buff.index("}")
        array.append([float(val.strip()) for val in buff[start+1:end].split(",")])
        buff = buff[end+1:]

f.close()

print(array)

如果需要将算术表达式扩展到一级乘法，可以执行以下操作：

import operator

def prod(lst):
    return reduce(operator.mul, lst, 1)

f = open("filename", "r")

buff = ""
array = []
for line in f:
    buff += line
    if "}" in line:
        start = buff.index("{")
        end = buff.index("}")
        array.append([prod(float(factor.strip()) for factor in val.split("*")) for val in buff[start+1:end].split(",")])
        buff = buff[end+1:]

f.close()

print(array)

---

要了解发生了什么，请先看和。

这里有一些代码，可以让换行符出现在您喜欢的任何地方。但是条目只能是浮点数

f = open("filename", "r")

buff = ""
array = []
for line in f:
    buff += line
    if "}" in line:
        start = buff.index("{")
        end = buff.index("}")
        array.append([float(val.strip()) for val in buff[start+1:end].split(",")])
        buff = buff[end+1:]

f.close()

print(array)

如果需要将算术表达式扩展到一级乘法，可以执行以下操作：

import operator

def prod(lst):
    return reduce(operator.mul, lst, 1)

f = open("filename", "r")

buff = ""
array = []
for line in f:
    buff += line
    if "}" in line:
        start = buff.index("{")
        end = buff.index("}")
        array.append([prod(float(factor.strip()) for factor in val.split("*")) for val in buff[start+1:end].split(",")])
        buff = buff[end+1:]

f.close()

print(array)

---

要想了解发生了什么，先看看和。eval是邪恶的，但有时它有它的位置。因为输入数据包含算术表达式，

eval

是转换它的最简单方法

当然，不要在不受信任的输入上运行此代码，因为它可能会危害您的计算机。（如果这些都是你从Mathematica生成的东西，你应该很安全）

代码如下：

m = eval('[' + text.replace('{','[').replace('}',']') + ']')
m = [[[x] for x in row] for row in m]

在

111.txt

文件上运行此命令（使用

text=open（'111.txt'）.read（）

）会产生预期的结果：

[[[-0.00036], [1], [0], [1], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0]], [[0.0003], [-1.00026], [2], [0], [1], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0]], [[0], [0.0002], [-2], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0]], [[1e-05], [0], [0], [-1], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0]], [[0], [1e-05], [0], [0], [-1], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0]], [[5e-05], [0], [0], [0], [0], [-0.01], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0]], [[0], [5e-05], [0], [0], [0], [0], [-0.01], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0]], [[0], [0], [0], [0], [0], [0.01], [0], [-0.000344], [1], [0], [1], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0]], [[0], [0], [0], [0], [0], [0], [0.01], [0.0003], [-1.000244], [2], [0], [1], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0]], [[0], [0], [0], [0], [0], [0], [0], [0], [0.0002], [-2], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0]], [[0], [0], [0], [0], [0], [0], [0], [1e-05], [0], [0], [-1], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0]], [[0], [0], [0], [0], [0], [0], [0], [0], [1e-05], [0], [0], [-1], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0]], [[0], [0], [0], [0], [0], [0], [0], [3.4e-05], [0], [0], [0], [0], [-0.01], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0]], [[0], [0], [0], [0], [0], [0], [0], [0], [3.4e-05], [0], [0], [0], [0], [-0.01], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0]], [[0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0.01], [0], [-0.000328], [1], [0], [1], [0], [0], [0], [0], [0], [0]], [[0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0.01], [0.0003], [-1.000228], [2], [0], [1], [0], [0], [0], [0], [0]], [[0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0.0002], [-2], [0], [0], [0], [0], [0], [0], [0]], [[0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [1e-05], [0], [0], [-1], [0], [0], [0], [0], [0], [0]], [[0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [1e-05], [0], [0], [-1], [0], [0], [0], [0], [0]], [[0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [1.8e-05], [0], [0], [0], [0], [-0.01], [0], [0], [0], [0]], [[0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [1.8e-05], [0], [0], [0], [0], [-0.01], [0], [0], [0]], [[0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0.01], [0], [-0.0003], [1], [0]], [[0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0.01], [0.0003], [-1.0002], [2]], [[0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0.0002], [-2]]]

---

eval

是邪恶的，但有时它也有它的位置。因为输入数据包含算术表达式，

eval

是转换它的最简单方法

当然，不要在不受信任的输入上运行此代码，因为它可能会危害您的计算机。（如果这些都是你从Mathematica生成的东西，你应该很安全）

代码如下：

m = eval('[' + text.replace('{','[').replace('}',']') + ']')
m = [[[x] for x in row] for row in m]

在

111.txt

文件上运行此命令（使用

text=open（'111.txt'）.read（）

）会产生预期的结果：

[[[-0.00036], [1], [0], [1], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0]], [[0.0003], [-1.00026], [2], [0], [1], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0]], [[0], [0.0002], [-2], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0]], [[1e-05], [0], [0], [-1], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0]], [[0], [1e-05], [0], [0], [-1], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0]], [[5e-05], [0], [0], [0], [0], [-0.01], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0]], [[0], [5e-05], [0], [0], [0], [0], [-0.01], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0]], [[0], [0], [0], [0], [0], [0.01], [0], [-0.000344], [1], [0], [1], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0]], [[0], [0], [0], [0], [0], [0], [0.01], [0.0003], [-1.000244], [2], [0], [1], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0]], [[0], [0], [0], [0], [0], [0], [0], [0], [0.0002], [-2], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0]], [[0], [0], [0], [0], [0], [0], [0], [1e-05], [0], [0], [-1], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0]], [[0], [0], [0], [0], [0], [0], [0], [0], [1e-05], [0], [0], [-1], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0]], [[0], [0], [0], [0], [0], [0], [0], [3.4e-05], [0], [0], [0], [0], [-0.01], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0]], [[0], [0], [0], [0], [0], [0], [0], [0], [3.4e-05], [0], [0], [0], [0], [-0.01], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0]], [[0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0.01], [0], [-0.000328], [1], [0], [1], [0], [0], [0], [0], [0], [0]], [[0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0.01], [0.0003], [-1.000228], [2], [0], [1], [0], [0], [0], [0], [0]], [[0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0.0002], [-2], [0], [0], [0], [0], [0], [0], [0]], [[0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [1e-05], [0], [0], [-1], [0], [0], [0], [0], [0], [0]], [[0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [1e-05], [0], [0], [-1], [0], [0], [0], [0], [0]], [[0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [1.8e-05], [0], [0], [0], [0], [-0.01], [0], [0], [0], [0]], [[0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [1.8e-05], [0], [0], [0], [0], [-0.01], [0], [0], [0]], [[0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0.01], [0], [-0.0003], [1], [0]], [[0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0.01], [0.0003], [-1.0002], [2]], [[0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0], [0.0002], [-2]]]

---

---

在文本文件的一行上总是恰好有一行数组吗？不，有时它可以跳转，但仍然有{}您的原始数据，因为发布在Ashwinis答案下包含算术表达式！你应该考虑使用或类似的东西。是的，对不起，我没注意到，是我的错。你能帮我处理原始数据吗？在Dropbox上的文件有我所需要的。当然，DmitriyButenko：如果你想做进一步的计算，可以考虑使用NUMPY。在处理数字矩阵时，它将提供速度和灵活性。文本文件的一行上是否总是正好有一行数组？不，有时它可以跳转，但仍然有{}您的原始数据，如Ashwinis答案下发布的包含算术表达式！你应该考虑使用或类似的东西。是的，对不起，我没注意到，是我的错。你能帮我处理原始数据吗？在Dropbox上的文件有我所需要的。当然，DmitriyButenko：如果你想做进一步的计算，可以考虑使用NUMPY。使用数字矩阵时，它将提供速度和灵活性。

Traceback（最近一次调用最后一次）：文件“/Users/twillightwind/Desktop/mas/prog.pyw”，第6行，在.rstrip（'}、\n'）.lstrip（'{'）.split（'，'））中的项中，在f]文件“/System/Library/Frameworks/Python.framework/Versions/2.7/ast.py”中的行，第49行，在literal_eval File“/System/Library/Frameworks/Python.Frameworks/Versions/2.7/lib/python2.7/ast.py”中，第37行，在解析文件“”中，第10行，^SyntaxError:invalid syntax[Finished]

@dmitriybtenko请发布文件的实际内容，我的回答对样本数据很有效。@Ashwini：OP在评论中说行可以跨越多行。这可能就是问题所在。@unutbu实际数据包含类似于

3.40*0.00001

，我想这是引起错误的原因。@Ashwini:行以

\r

结尾，而不是

\n

回溯（最后一次调用）：文件“/Users/twillightwind/Desktop/mas/prog.pyw”，第6行，在.rstrip（'}、\n'）.lstrip（'{）行的项中.split（“，”）]f]文件“/System/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/ast.py”中的第49行“/System/Library/Frameworks/Python.Frameworks/Versions/2.7/ast.py”，第37行，解析文件“，”第10行，^syntaxer:无效语法[已完成]@Dmitriybteneko请您发布文件的实际内容，我的答案适用于样本数据。@Ashwini:OP在评论中说行可能跨越多行。这可能就是问题所在。@unutbu实际数据包含类似于

3.40*0.00001

，我想这可能会引起错误。@Ashwini:行以

\r

结尾，而不是

\n

。是的，这适用于没有nm结构的文件，谢谢！嗯，nm解析仍然有一个问题。@DmitriyButenko:我现在也添加了这个。非常感谢！这完全解决了我的问题，也感谢链接，现在我知道它是如何工作的。是的，这对没有nm结构的文件有效，谢谢！嗯，nm解析仍然有一个问题。@DmitriyButenko:我现在也添加了这个。非常感谢！这完全解决了我的问题，也感谢链接，现在我知道它是如何工作的了。