Python 使一个三角网格交错
我在这里使用这个grid.py着色程序 生成网格的相关代码是Python 使一个三角网格交错,python,tkinter,grid,tkinter-canvas,Python,Tkinter,Grid,Tkinter Canvas,我在这里使用这个grid.py着色程序 生成网格的相关代码是 self.cells = [] for iy in range(n): for ix in range(n): xpad, ypad = pad * (ix+1), pad * (iy+1) x, y = xpad + ix*xsize, ypad + iy*ysize rect = self.w.create_rectangle(x, y
self.cells = []
for iy in range(n):
for ix in range(n):
xpad, ypad = pad * (ix+1), pad * (iy+1)
x, y = xpad + ix*xsize, ypad + iy*ysize
rect = self.w.create_rectangle(x, y, x+xsize,
y+ysize, fill=UNFILLED)
self.cells.append(rect)
我想知道我是否可以得到它,使方块交错如下所示:
您可以为给定行上单元格的每个x坐标添加/减去“交错偏移”。通过将偏移量乘以(-1)**行
,由“行”的秩确定的值的符号
也许像这样
self.cells = []
for row in range(n):
stagger_offset = (xsize // 4) * (-1)**row # will be positive for even rows, negative otherwise
y0 = pad * (row + 1) + row * ysize
y1 = y0 + ysize
for col in range(n):
x0 = pad * (col + 1) + col * xsize + stagger_offset
x1 = x0 + xsize
self.cells.append(self.w.create_rectangle(x0, y0, x1, y1, fill=UNFILLED))
您可能需要在偶数行/奇数行的开头/结尾插入半个单元格,具体取决于您喜欢的视觉效果