在二维字典中按两个字段对python对象分组

我有一个python类

剧集

，它有两个字段：

季节

和

数字

。我在

剧集列表

中有一个对象列表。这张单子是按季节排列的，然后是按情节排列的。在下面的示例中，数据是按此顺序创建的。 我想做的是：我想创建一个

seasure

对象的字典。每个

季节

对象也有一个字典作为名为

剧集

的字段。本词典应包含所有具有本季编号的

插曲

对象。 在下面的最小示例的末尾，我打印了分组数据，结果是：

S3E1
S3E2
S3E3
S3E1
S3E2
S3E3
S3E1
S3E2
S3E3

# required classes
class Episode:
    def __init__(self, season, number):
        self.season = season
        self.number = number


class Season:
    episodes = {}

    def __init__(self, number):
        self.number = number

# create episode data
episode_list = []
for i in range(3):
    episode_list.append(Episode(1, i+1))

for i in range(3):
    episode_list.append(Episode(2, i+1))

for i in range(3):
    episode_list.append(Episode(3, i+1))

# group episodes by seasons
seasons = {}
for episode in episode_list:
    for season_number in range(1, 4):
        season = Season(season_number)
        for episode in episode_list:
            if episode.season == season_number:
                season.episodes[episode.number] = episode
        seasons[season_number] = season

# print result
for sn, s in seasons.items():
    for en, e in s.episodes.items():
        print "S" + str(e.season) + "E" +  str(e.number)

这是错误的，（根据我创建的数据）应该是：

S1E1
S1E2
S1E3
S2E1
S2E2
S2E3
S3E1
S3E2
S3E3

# required classes
class Episode:
    def __init__(self, season, number):
        self.season = season
        self.number = number


class Season:
    episodes = {}

    def __init__(self, number):
        self.number = number

# create episode data
episode_list = []
for i in range(3):
    episode_list.append(Episode(1, i+1))

for i in range(3):
    episode_list.append(Episode(2, i+1))

for i in range(3):
    episode_list.append(Episode(3, i+1))

# group episodes by seasons
seasons = {}
for episode in episode_list:
    for season_number in range(1, 4):
        season = Season(season_number)
        for episode in episode_list:
            if episode.season == season_number:
                season.episodes[episode.number] = episode
        seasons[season_number] = season

# print result
for sn, s in seasons.items():
    for en, e in s.episodes.items():
        print "S" + str(e.season) + "E" +  str(e.number)

---

在这里，您已经创建了一个类属性

class Season:
    episodes = {}

    def __init__(self, number):
        self.number = number

class Season:    
    def __init__(self, number):
        self.episodes = {}
        self.number = number

这意味着在所有季节实例中共享相同的dict

您应该将其设置为实例属性

class Season:
    episodes = {}

    def __init__(self, number):
        self.number = number

class Season:    
    def __init__(self, number):
        self.episodes = {}
        self.number = number

这是你的问题：

class Season:
    episodes = {}

剧集

是类属性。所有

季

s共享相同的

剧集

dict。您需要将

剧集

设置为实例属性，如下所示：

def __init__(self, number):
    self.episodes = {}
    self.number = number

所有其他属性都正确，所以这是一个类属性而不是实例属性，这有点奇怪

另外，请注意在字典上循环：

for sn, s in seasons.items():
    for en, e in s.episodes.items():

不保证会下任何特别的订单。你可能会在第一季之前结束第二季。如果有必要，您可以使用排序的

循环：

for sn, s in sorted(seasons.items()):
    for en, e in sorted(s.episodes.items()):

非常感谢，这绝对解决了我的问题。和往常一样，最终这是显而易见的。但在花了很长时间研究这个之后，我再也看不到它了；）非常感谢你的帮助。另外，你最后的评论非常有用，我可以肯定地用它来确保我得到了正确的顺序。非常感谢！