Python 我正试图从一个需要登录但没有得到任何数据的网站上抓取HTML

但是，当我运行python时，似乎无法获取任何数据。我得到一个HTTP状态码200和

状态。ok

返回一个真值。任何帮助都会很好。这是我在终端中的响应：

[]

200

True

import requests
from lxml import html

USERNAME = "username@email.com"
PASSWORD = "legitpassword"

LOGIN_URL = "https://bitbucket.org/account/signin/?next=/"
URL = "https://bitbucket.org/dashboard/overview"

def main():
session_requests = requests.session()

# Get login csrf token
result = session_requests.get(LOGIN_URL)
tree = html.fromstring(result.text)
authenticity_token = list(set(tree.xpath("//input[@name='csrfmiddlewaretoken']/@value")))[0]

# Create payload
payload = {
    "username": USERNAME, 
    "password": PASSWORD, 
    "csrfmiddlewaretoken": authenticity_token
}

# Perform login
result = session_requests.post(LOGIN_URL, data = payload, headers = dict(referer = LOGIN_URL))

# Scrape url
result = session_requests.get(URL, headers = dict(referer = URL))
tree = html.fromstring(result.content)
bucket_elems = tree.findall(".//span[@class='repo-name']")
bucket_names = [bucket_elem.text_content().replace("\n", "").strip() for bucket_elem in bucket_elems]

print bucket_names
print result.status_code

if __name__ == '__main__':
main()

---

xpath错误，类repo名称没有span，您可以通过以下方式从锚定标记获取repo名称：

bucket_elems = tree.xpath("//a[@class='execute repo-list--repo-name']")
bucket_names = [bucket_elem.text_content().strip() for bucket_elem in bucket_elems]

自编写教程以来，html已经发生了明显的变化