迭代计数器Python3x

因此，我用Python构建了一个简单的计算器，用户输入两个数字和一个运算符，然后给出答案。他们还可以选择再次运行计算器。我想对答案进行编号，使每个答案都显示“答案1等于x”，“答案2等于x”，等等，这取决于计算器运行的次数。每次我试图设置计数器的格式来计算迭代次数时，它都不起作用，只能一遍又一遍地将它们标记为“答案1”。任何帮助都将不胜感激。我对Python非常陌生

answer = "y"

while ((answer == "Y") or (answer == "y") or (answer == "Yes") or (answer == "yes")):
    numones = input ("Give me a number: ")
    numtwos = input ("Give me another number: ")

    numone = float(numones)
    numtwo = float(numtwos)

    operation = input ("Give me an operation (+,-,*,/): ")

    counter = 0
    for y in answer:
        counter += 1

    if (operation == "+"):
        calc = numone + numtwo
        print ("Answer " + str(counter) + " is " + str(calc))
    elif (operation == "-"):
        calc = numone - numtwo
        print ("Answer " + str(counter) + " is " + str(calc))
    elif (operation == "*"):
        calc = numone * numtwo
        print ("Answer " + str(counter) + " is " + str(calc))
    elif (operation == "/"):
        calc = numone / numtwo
        if (numtwo != 0):
            print ("Answer " + str(counter) + " is " + str(calc))
        else:
            print ("You can't divide by zero.")
    else:    
        print ("Operator not recognized.")

    answer = input ("Do you want to keep going? ")
    if ((answer == "Y") or (answer == "y") or (answer == "Yes") or (answer == "yes")):
        print ()
    else:
        print ("Goodbye.")
        break

---

删除

while

循环中的

计数器=0

。并将此声明移动到

while

循环上方

另外，行：

for y in answer:
    counter += 1

---

你真的很困惑，而且肯定是错的，因为如果你的答案是“是”，你会得到+3的增长。只需增加（

counter+=1

）

counter

，无需任何

for

-循环。

，因为在

中不断分配
counter=0
，而在
循环中。只需注意-您可以使用
在['y'，'y'，'yes'，'yes中回答]
而不是将
答案
与每个可能的值进行比较。