在Python中使用BeautifulSoup提取链接标记之间的文本

我的HTML代码如下所示：

<a href="/Content.aspx?id=102966" id="mylink" target="_blank">EZSTORAGE - PACK IT. STORE IT. WIN - <img src="/images/usa.png" style="border:none; height:14px; margin-bottom:-2px;"/> Nationwide - <span title="college students/staff of schools in valid states">Restrictions</span> - Ends 6/30/15</a>

---

如有任何见解，将不胜感激

你不能像这样使用

link.text

而不是

link.contents

text = """
<a href="/Content.aspx?id=102966" id="mylink" target="_blank">EZSTORAGE - PACK IT. STORE IT. WIN - <img src="/images/usa.png" style="border:none; height:14px; margin-bottom:-2px;"/> Nationwide - <span title="college students/staff of schools in valid states">Restrictions</span> - Ends 6/30/15</a>
"""
from bs4 import BeautifulSoup

soup = BeautifulSoup(text)

for link in soup.find_all('a', id='mylink'):
    link_text = link.text
    print link_text

---

您可以使用正则表达式查找所有文本

import urllib,urllib2,re

content=r'<a href="/Content.aspx?id=102966" id="mylink" target="_blank">EZSTORAGE - PACK IT. STORE IT. WIN - <img src="/images/usa.png" style="border:none; height:14px; margin-bottom:-2px;"/> Nationwide - <span title="college students/staff of schools in valid states">Restrictions</span> - Ends 6/30/15</a>''



links=re.findall(r'>(.*?)<',content)
a=""
for link in links:
    a=a+link
print a

导入urllib、urllib2、re 内容=r'' links=re.findall（r'>（.*）

EZSTORAGE - PACK IT. STORE IT. WIN -  Nationwide - Restrictions - Ends 6/30/15

import urllib,urllib2,re

content=r'<a href="/Content.aspx?id=102966" id="mylink" target="_blank">EZSTORAGE - PACK IT. STORE IT. WIN - <img src="/images/usa.png" style="border:none; height:14px; margin-bottom:-2px;"/> Nationwide - <span title="college students/staff of schools in valid states">Restrictions</span> - Ends 6/30/15</a>''



links=re.findall(r'>(.*?)<',content)
a=""
for link in links:
    a=a+link
print a