Spark-toDebugString在python中不好

这是我在scala中使用编辑字符串时得到的：

scala> val a  = sc.parallelize(Array(1,2,3)).distinct
a: org.apache.spark.rdd.RDD[Int] = MappedRDD[3] at distinct at <console>:12

scala> a.toDebugString
res0: String = 
(4) MappedRDD[3] at distinct at <console>:12
 |  ShuffledRDD[2] at distinct at <console>:12
 +-(4) MappedRDD[1] at distinct at <console>:12
    |  ParallelCollectionRDD[0] at parallelize at <console>:12

>>> a = sc.parallelize([1,2,3]).distinct()
>>> a.toDebugString()
'(4) PythonRDD[6] at RDD at PythonRDD.scala:43\n |  MappedRDD[5] at values at NativeMethodAccessorImpl.java:-2\n |  ShuffledRDD[4] at partitionBy at NativeMethodAccessorImpl.java:-2\n +-(4) PairwiseRDD[3] at RDD at PythonRDD.scala:261\n    |  PythonRDD[2] at RDD at PythonRDD.scala:43\n    |  ParallelCollectionRDD[0] at parallelize at PythonRDD.scala:315'

如您所见，python中的输出不如scala中的好。有什么技巧可以让这个函数有更好的输出吗

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我正在使用Spark 1.1.0

尝试添加

print

语句，以便实际打印调试字符串，而不是显示其

\uuuu repr\uuu

：

>>> a = sc.parallelize([1,2,3]).distinct()
>>> print a.toDebugString()
(8) PythonRDD[27] at RDD at PythonRDD.scala:44 [Serialized 1x Replicated]
 |  MappedRDD[26] at values at NativeMethodAccessorImpl.java:-2 [Serialized 1x Replicated]
 |  ShuffledRDD[25] at partitionBy at NativeMethodAccessorImpl.java:-2 [Serialized 1x Replicated]
 +-(8) PairwiseRDD[24] at distinct at <stdin>:1 [Serialized 1x Replicated]
    |  PythonRDD[23] at distinct at <stdin>:1 [Serialized 1x Replicated]
    |  ParallelCollectionRDD[21] at parallelize at PythonRDD.scala:358 [Serialized 1x Replicated]

a=sc.parallelize（[1,2,3]）.distinct（） >>>打印a.toDebugString（） （8） PythonRDD.scala:44[序列化1x复制] |NativeMethodAccessorImpl.java处的值处的MappedRDD[26]：-2[序列化1x复制] |NativeMethodAccessorImpl.java分区中的Shuffledd[25]：-2[序列化1x复制] +-（8） 不同位置处的成对ISERDD[24]：1[序列化1x复制] |PythonRDD[23]位于不同的位置：1[序列化1x复制] |PythonRDD.scala:358[序列化1x复制]

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它没有被执行，只是被缓存 你应使用：

a = sc.parallelize([1,2,3]).distinct()
a.collect()
[1, 2, 3]