如何删除python列表中字符串的一部分？

我有以下代码输出（使用键盘模块）：

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如何从列表中删除每个“键盘事件”？

尝试使用循环删除此事件：

list = [KeyboardEvent(enter up), KeyboardEvent(h down), KeyboardEvent(h up), KeyboardEvent(e down), KeyboardEvent(e up), KeyboardEvent(y down), KeyboardEvent(y up)]

for x in list:
    del list[str(x)]

此列表压缩应该可以使用

使用以下方法如何：

为了获得更好的结果，您可以将此与以下内容结合使用：

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演示：

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我想试试正则表达式

import re

Foo = [KeyboardEvent(enter up), KeyboardEvent(h down), KeyboardEvent(h up), KeyboardEvent(e down), KeyboardEvent(e up), KeyboardEvent(y down), KeyboardEvent(y up)]

strList = []

for item in Foo:
  bar = re.sub('KeyboardEvent(\(.*?)', '', str(item))
  bar = re.sub('\)', '', bar)
  strList.append(bar)

print strList

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或者，您也可以尝试将键盘事件作为字符串删除：

a=[KeyboardEvent(enter up), KeyboardEvent(h down), KeyboardEvent(h up), KeyboardEvent(e down), KeyboardEvent(e up), KeyboardEvent(y down), KeyboardEvent(y up)]
a=[str(elem).strip('KeyboardEvent') for elem in a]

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请清楚您的列表元素。此列表中似乎没有字符串；相反，它们是对象（类KeyboardEvent的单个实例）。最简单的方法就是

list=[]

。是否有一个特定的事件包含您想要删除的某个键盘操作（如“enter up”）？如果它不是键盘事件怎么办？它仍然可以工作。它适用于删除列表/数组中的任何内容。然后你可以使用

list=[]

True，更简单。不建议在PythonCan中使用list作为变量名。不要责怪你完全按照他的要求去做，但这会产生一个空列表，这显然不是目标。@ChristianDean我不知道。你能解释一下原因吗？@ChristianDean，这就是你想要的吗？@Ajax1234当然。它是首选的，因为

实例

考虑了子类，而

类型

不考虑。这里是相关的。['（输入up），KeyboardEvent（h down），KeyboardEvent（h up），KeyboardEvent（e down），KeyboardEvent（e up），KeyboardEvent（y down），KeyboardEvent（y up）”，它只删除了第一个。效果很好，但我仍然喜欢@Vinícius Aguiar回答更多。不管怎样，还是向上投票。

newList = [event.name for event in myList]

newList = [event.name + ' ' + event.event_type for event in myList]

>>> myList
[KeyboardEvent(enter up), KeyboardEvent(h down), KeyboardEvent(h up), KeyboardEvent(e down), KeyboardEvent(e up), KeyboardEvent(y down)]

>>> [event.name for event in myList]
['enter', 'h', 'h', 'e', 'e', 'y']

>>> [event.name + ' ' + event.event_type for event in myList]
['enter up', 'h down', 'h up', 'e down', 'e up', 'y down']

import re

Foo = [KeyboardEvent(enter up), KeyboardEvent(h down), KeyboardEvent(h up), KeyboardEvent(e down), KeyboardEvent(e up), KeyboardEvent(y down), KeyboardEvent(y up)]

strList = []

for item in Foo:
  bar = re.sub('KeyboardEvent(\(.*?)', '', str(item))
  bar = re.sub('\)', '', bar)
  strList.append(bar)

print strList

a=[KeyboardEvent(enter up), KeyboardEvent(h down), KeyboardEvent(h up), KeyboardEvent(e down), KeyboardEvent(e up), KeyboardEvent(y down), KeyboardEvent(y up)]
a=[str(elem).strip('KeyboardEvent') for elem in a]