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Python 如何在django查询中排序?_Python_Django_Django Queryset - Fatal编程技术网

Python 如何在django查询中排序?

Python 如何在django查询中排序?,python,django,django-queryset,Python,Django,Django Queryset,我在django中有一个名为User as custom User model的表。 我有另一个名为Portfolio和ProjectDetail的模型,它与我的用户模型有ForeignKey关系。表结构如下所示: class ProjectDetail(models.Model): user = models.ForeignKey(settings.AUTH_USER_MODEL) title = models.TextField() category = models

我在django中有一个名为User as custom User model的表。 我有另一个名为
Portfolio
ProjectDetail
的模型,它与我的
用户
模型有
ForeignKey
关系。表结构如下所示:

class ProjectDetail(models.Model):
    user = models.ForeignKey(settings.AUTH_USER_MODEL)
    title = models.TextField()
    category = models.CharField(max_length=50, choices=CATEGORY_CHOICES)
    description = models.TextField(null=True, blank=True)
    vote_count = models.IntegerField(default=0) 

class Portfolio(models.Model):
    user = models.ForeignKey(settings.AUTH_USER_MODEL)
    project = models.ForeignKey(ProjectDetail, null=True, blank=True)
    description = models.TextField(null=True, blank=True)
用户模型为:

class User(AbstractBaseUser, PermissionsMixin):
    username = models.CharField(_('Username'), unique=True, max_length=100, blank=False, null=False,
        help_text=_('20 characters or fewer. Letters, numbers and -/_ characters, no capitals, no spaces'),
    )
    first_name = models.CharField(_('First Name'), max_length=30, blank=True, null=True)
    middle_name = models.CharField(_('Middle Name'), max_length=30, blank=True, null=True)
    last_name = models.CharField(_('Last Name'), max_length=30, blank=True, null=True)
    about_yourself = models.TextField(null=True, blank=True)
我想找到上传项目最多的用户列表,或者找到公文包最多的用户列表。如何找到按
ProjecDetail
数量或
Portfolio
数量排序的用户排序列表?

用于分组依据:

from django.db.models import Count

#group by portfolios count
User.objects.annotate(portfolios=Count('portfolio')).order_by('portfolios')
#group by projects count
User.objects.annotate(projects=Count('portfolio__project')).order_by('projects')

您正在寻找注释/聚合。见备忘单。