Python Jupyter笔记本显示FileNotFoundError，无法运行任何shell

我已经安装了Jupyter：

操作系统：32位windows 7

jupyter笔记本的版本是6.0.1

安装后，当我试图打开笔记本时，它显示一个内核错误：

Traceback (most recent call last):
  File "E:\Jupyter\miniconda3\lib\site-packages\tornado\web.py", line 1703, in _execute
    result = await result
  File "E:\Jupyter\miniconda3\lib\site-packages\tornado\gen.py", line 742, in run
    yielded = self.gen.throw(*exc_info)  # type: ignore
  File "E:\Jupyter\miniconda3\lib\site-packages\notebook\services\sessions\handlers.py", line 72, in post
    type=mtype))
  File "E:\Jupyter\miniconda3\lib\site-packages\tornado\gen.py", line 735, in run
    value = future.result()
  File "E:\Jupyter\miniconda3\lib\site-packages\tornado\gen.py", line 742, in run
    yielded = self.gen.throw(*exc_info)  # type: ignore
  File "E:\Jupyter\miniconda3\lib\site-packages\notebook\services\sessions\sessionmanager.py", line 88, in create_session
    kernel_id = yield self.start_kernel_for_session(session_id, path, name, type, kernel_name)
  File "E:\Jupyter\miniconda3\lib\site-packages\tornado\gen.py", line 735, in run
    value = future.result()
  File "E:\Jupyter\miniconda3\lib\site-packages\tornado\gen.py", line 742, in run
    yielded = self.gen.throw(*exc_info)  # type: ignore
  File "E:\Jupyter\miniconda3\lib\site-packages\notebook\services\sessions\sessionmanager.py", line 101, in start_kernel_for_session
    self.kernel_manager.start_kernel(path=kernel_path, kernel_name=kernel_name)
  File "E:\Jupyter\miniconda3\lib\site-packages\tornado\gen.py", line 735, in run
    value = future.result()
  File "E:\Jupyter\miniconda3\lib\site-packages\tornado\gen.py", line 209, in wrapper
    yielded = next(result)
  File "E:\Jupyter\miniconda3\lib\site-packages\notebook\services\kernels\kernelmanager.py", line 168, in start_kernel
    super(MappingKernelManager, self).start_kernel(**kwargs)
  File "E:\Jupyter\miniconda3\lib\site-packages\jupyter_client\multikernelmanager.py", line 110, in start_kernel
    km.start_kernel(**kwargs)
  File "E:\Jupyter\miniconda3\lib\site-packages\jupyter_client\manager.py", line 259, in start_kernel
    **kw)
  File "E:\Jupyter\miniconda3\lib\site-packages\jupyter_client\manager.py", line 204, in _launch_kernel
    return launch_kernel(kernel_cmd, **kw)
  File "E:\Jupyter\miniconda3\lib\site-packages\jupyter_client\launcher.py", line 138, in launch_kernel
    proc = Popen(cmd, **kwargs)
  File "E:\Jupyter\miniconda3\lib\subprocess.py", line 800, in __init__
    restore_signals, start_new_session)
  File "E:\Jupyter\miniconda3\lib\subprocess.py", line 1207, in _execute_child
    startupinfo)
FileNotFoundError: [WinError 2] The system cannot find the file specified

因为这个原因，我不能用Jupyter运行任何东西。

---

如何修复它？

这是您的环境的问题。以下是调试它的方法：

检查Jupyter配置中指定的内核（请参阅Linux上的

%APPDATA%\Jupyter\kernels\\kernel.json

/

~/.local/share/Jupyter/kernels//kernel.json）是否可以通过命令行启动

例如，在我的
kernel.json
文件中，有：

{
 "argv": [
  "/home/mrmino/.virtualenvs/taf/bin/python3.7",
  "-m",
  "ipykernel_launcher",
  "-f",
  "{connection_file}"
 ],
 "display_name": "Python 3",
 "language": "python"
}

因此，在我的系统上，命令
/home/mrmino/.virtualenvs/taf/bin/python3.7-m ipykernel_启动器
应该启动ipython内核

如果在您的系统上没有，您必须安装它或在JSON内核规范文件中手动更正它。
我在“C:\Users\abc\AppData\Local\Programs\Python\Python38-32\share\jupyter\kernels\python3”中找到kernels.JSON文件，它包含以下代码：
{“argv”：[“Python”、“-m”、“ipykernel\u启动器”、“-f”、“{connection\u file}]，“display_name”：“Python 3”，“language”：“Python”}
我认为它在第二行延迟了，那么我应该提供哪种Python呢？conda environment python还是普通python？@Akshatsah是
-m ipykernel_launcher
的工作环境。可能就是你开始使用Jupyter的那个。@BlazejMichanlik这有点棘手，因为我在“E:/”中安装了conda环境，anaconda提示符以“C:/”打开，所以我在使用它时遇到了问题，而且我的系统中安装了不止一个python，比如conda、3.7和3.8，所以你能帮我一下吗。谢谢：）@akshatsah这不是关于蟒蛇提示，而是关于系统的
cmd
。为解释器二进制文件设置一个完整路径，它应该可以工作。正如我在编辑中提到的那样，我改变了.json文件。谢谢你的关心和帮助，我真的很感激。谢谢：）