Python 访问FlaskAPI中的第二个资源

我有一个使用Flask的简单Api，它使用下面的代码返回字符串列表：

from flask import Flask, request
from flask_restful import Resource, Api
from json import dumps

app = Flask(__name__)
api = Api(app)

class Product(Resource):
    def get(self):
        return {'products':['A','B','C','D','E','F','G','H','I','J','K']}

class Accounting(Resource):
    def get(self):
        return {'accounting':['1','2','3','4','5','6','7','8','9']}

api.add_resource(Product, '/')
api.add_resource(Accounting, '/')

if __name__ == '__main__':
    app.run(host='0.0.0.0', port=80, debug=True)

当我使用以下代码时，我可以访问FlaskAPI中定义的列表。这列出了“产品”资源的内容

我遇到的问题是访问第二个资源“accounting”。当使用下面的代码（使用PHP）时，甚至当我只是转到网页的主页地址时，我都无法看到或访问这些资源

<?php
        $json = file_get_contents('http://product-service/');
        $obj = json_decode($json);
        $accounts = $obj->accounting;
        echo "$accounts[0]";
?>

有人能给我指出正确的方向吗

提前谢谢

---

Michael

您在一个路径下安装了两个API：根路径“/”，我建议将产品和记帐分离到单独的API点：

from flask import Flask, request
from flask_restful import Resource, Api
from json import dumps

app = Flask(__name__)
api = Api(app)

class Product(Resource):
    def get(self):
        return {'products':['A','B','C','D','E','F','G','H','I','J','K']}

class Accounting(Resource):
    def get(self):
        return {'accounting':['1','2','3','4','5','6','7','8','9']}

api.add_resource(Product, '/products')
api.add_resource(Accounting, '/accounting')

if __name__ == '__main__':
    app.run(host='0.0.0.0', port=80, debug=True)

---

嘿，它起作用了！，我使用了上面的建议，并将此代码添加到php部分

$json=file\u get\u contents（'http://product-service/accounting');谢谢：）
from flask import Flask, request
from flask_restful import Resource, Api
from json import dumps

app = Flask(__name__)
api = Api(app)

class Product(Resource):
    def get(self):
        return {'products':['A','B','C','D','E','F','G','H','I','J','K']}

class Accounting(Resource):
    def get(self):
        return {'accounting':['1','2','3','4','5','6','7','8','9']}

api.add_resource(Product, '/products')
api.add_resource(Accounting, '/accounting')

if __name__ == '__main__':
    app.run(host='0.0.0.0', port=80, debug=True)