Python 类型错误：Int对象不可调用

当我尝试运行代码时，代码出现错误

代码

print("Operations: \n1. Addition \n2. Subtraction \n3: Multiplication \n4. Division")
print("^ Operation 'ID' please enter the id of your choice")
choice = input()
num1 = input("Enter your first number: ")
num2 = input("Enter your second number: ")
def addition(num1, num2):
    num1
    num2
    ans = num1 + num2
    print('Your answer is %s') %(ans)
def subtraction(num1, num2):
    num1
    num2
    ans = num1 - num2
    print('Your answer is %s') %(ans)
def multiply(num1, num2):
    num1
    num2
    ans = num1 * num2
    print('Your answer is %s') %(ans)
def division(num1, num2):
    num1
    num2
    ans = num1 / num2
    print('Your answer is %s') %(ans)
if choice == "1":
    addition
elif choice == "2":
    subtraction
elif choice == "3":
    multiply
elif choice == "4":
    division
else:
    print("Invalid Input")

    choice = int(input("Operations: \n1. Addition \n2. Subtraction \n3: Multiplication \n4. Division\n^ Operation 'ID' please enter the id of your choice\n"))
num1 = int(input("Enter your first number: "))
num2 = int(input("Enter your second number: "))
if choice == 1: #Addition
    num1
    num2
    ans = num1 + num2
    print("Your answer is " + str(ans))
elif choice == 2: #Subtraction
    num1
    num2
    ans = num1 - num2
    print("Your answer is " + str(ans))
elif choice == 3: #Miltiplication
    num1
    num2
    ans = num1 * num2
    print("Your answer is " + str(ans))
elif choice == 4: #Division
    num1
    num2
    ans = float(num1) / float(num2)
    print("Your answer is " + str(ans))

在调用python打印答案之前，一切都正常

---

我知道可能存在重复的代码，但是那里提供的代码都不起作用。

问题就是由于这个原因

if choice == 1():

应该在哪里

if choice == 1:

必须将num1和num2转换为整数类型

你应该调用函数，而不是声明它们

if choice == 1:
    addition(num1, num2)

你必须为其他事情做这件事

在做了所有的修改之后，你的程序看起来是这样的

print("Operations: \n1. Addition \n2. Subtraction \n3: Multiplication \n4. Division")
print("^ Operation 'ID' please enter the id of your choice")
choice = int(input())
num1 = int(input("Enter your first number: "))
num2 = int(input("Enter your second number: "))
def addition(num1, num2):
    ans = num1 + num2
    print('Your answer is %s') %(ans)
def subtraction(num1, num2):
    ans = num1 - num2
    print('Your answer is %s') %(ans)
def multiply(num1, num2):
    ans = num1 * num2
    print('Your answer is %s') %(ans)
def division(num1, num2):
    ans = num1 / num2
    print('Your answer is %s') %(ans)
if choice == 1:
    addition(num1,num2)
elif choice == 2:
    subtraction(num1,num2)
elif choice == 3:
    multiply(num1,num2)
elif choice == 4:
    division(num1,num2)
else:
    print("Invalid Input")

print('Your answer is %s' %ans)

我的更改是：

choice = int(input("Operations: \n1. Addition \n2. Subtraction \n3: Multiplication \n4. Division\n^ Operation 'ID' please enter the id of your choice\n"))
num1 = int(input("Enter your first number: "))
num2 = int(input("Enter your second number: "))
ans=None
if choice == 1:
    ans = num1 + num2
elif choice == 2:
    ans = num1 - num2
elif choice == 3:
    ans = num1 * num2
elif choice == 4:
    ans = float(num1) / num2
if  ans:
    print('Your answer is %s') %(ans)
else:
    print("Invalid Input")

---

问题就在眼前-

if choice == 1():
    addition
elif choice == 2():
    subtraction
elif choice == 3():
    multiply
elif choice == 4():
    division

我不知道你想要

1（）。您还应该调用函数
addition
等，比如-
addition（num1，num2）

而
选项
是
字符串
不是int。您应该将
num1
和
num2
转换为int

代码中的更多问题-

为什么要在函数中执行-
num1
和
num2
，它没有任何作用，可以删除每个函数的前两行

您的print函数错误，在Python 3.x中，
%（ans）
应该在函数内部，而不是外部

代码-

num1 = int(input("Enter your first number: "))
num2 = int(input("Enter your second number: "))
def addition(num1, num2):
    ans = num1 + num2
    print('Your answer is %s' %(ans))
def subtraction(num1, num2):
    ans = num1 - num2
    print('Your answer is %s' %(ans))
def multiply(num1, num2):
    ans = num1 * num2
    print('Your answer is %s' %(ans))
def division(num1, num2):
    ans = num1 / num2
    print('Your answer is %s' %(ans))
if choice == '1':
    addition(num1, num2)
elif choice == '2':
    subtraction(num1, num2)
elif choice == '3':
    multiply(num1, num2)
elif choice == '4':
    division(num1, num2)

当前代码中的错误只是打印语句中的括号。如果在print语句之外没有%ans，则代码在如下情况下工作

print("Operations: \n1. Addition \n2. Subtraction \n3: Multiplication \n4. Division")
print("^ Operation 'ID' please enter the id of your choice")
choice = int(input())
num1 = int(input("Enter your first number: "))
num2 = int(input("Enter your second number: "))
def addition(num1, num2):
    ans = num1 + num2
    print('Your answer is %s') %(ans)
def subtraction(num1, num2):
    ans = num1 - num2
    print('Your answer is %s') %(ans)
def multiply(num1, num2):
    ans = num1 * num2
    print('Your answer is %s') %(ans)
def division(num1, num2):
    ans = num1 / num2
    print('Your answer is %s') %(ans)
if choice == 1:
    addition(num1,num2)
elif choice == 2:
    subtraction(num1,num2)
elif choice == 3:
    multiply(num1,num2)
elif choice == 4:
    division(num1,num2)
else:
    print("Invalid Input")

print('Your answer is %s' %ans)

您刚刚编写的同一代码的整洁版本如下所示

print("Operations: \n1. Addition \n2. Subtraction \n3: Multiplication \n4. Division")
print("^ Operation 'ID' please enter the id of your choice")
choice = int(input())
num1 = int(input("Enter your first number: "))
num2 = int(input("Enter your second number: "))
def addition(num1, num2):
    ans = num1 + num2
    print('Your answer is %s') %(ans)
def subtraction(num1, num2):
    ans = num1 - num2
    print('Your answer is %s') %(ans)
def multiply(num1, num2):
    ans = num1 * num2
    print('Your answer is %s') %(ans)
def division(num1, num2):
    ans = num1 / num2
    print('Your answer is %s') %(ans)
if choice == 1:
    addition(num1,num2)
elif choice == 2:
    subtraction(num1,num2)
elif choice == 3:
    multiply(num1,num2)
elif choice == 4:
    division(num1,num2)
else:
    print("Invalid Input")

print('Your answer is %s' %ans)

print（“操作：\n1.加法\n2.减法\n3:乘法\n4.除法”）
打印（“^Operation'ID'请输入您选择的ID”）
choice=int（输入（））
num1=int（输入（“输入您的第一个数字：”）
num2=int（输入（“输入第二个数字：”）
def添加量（num1、num2）：
返回num1+num2
def减法（num1，num2）：
返回num1-num2
def倍增（num1，num2）：
返回num1*num2
def部门（num1、num2）：
返回num1/num2
如果选项==1：
ans=加法（num1，num2）
elif选项==2：
ans=减法（num1，num2）
elif选项==3：
ans=乘法（num1，num2）
elif选项==4：
ans=除法（num1，num2）
其他：
打印（“无效输入”）
如果在范围（4）中选择：
打印（'您的答案是%s'%1！'）
具有讽刺意味的是，尽管hid代码有点不合适，但我还是在@Vignesh Kalai的帮助下为自己的问题写了一个答案。因此，在做任何其他事情之前，我将解决对代码的更改

首先，与其定义我链接的每个操作，不如定义它们的“ID”

其次，我使用“+str（x）”打印答案，而不是使用%s这个公认的坏主意

修订代码

print("Operations: \n1. Addition \n2. Subtraction \n3: Multiplication \n4. Division")
print("^ Operation 'ID' please enter the id of your choice")
choice = input()
num1 = input("Enter your first number: ")
num2 = input("Enter your second number: ")
def addition(num1, num2):
    num1
    num2
    ans = num1 + num2
    print('Your answer is %s') %(ans)
def subtraction(num1, num2):
    num1
    num2
    ans = num1 - num2
    print('Your answer is %s') %(ans)
def multiply(num1, num2):
    num1
    num2
    ans = num1 * num2
    print('Your answer is %s') %(ans)
def division(num1, num2):
    num1
    num2
    ans = num1 / num2
    print('Your answer is %s') %(ans)
if choice == "1":
    addition
elif choice == "2":
    subtraction
elif choice == "3":
    multiply
elif choice == "4":
    division
else:
    print("Invalid Input")

    choice = int(input("Operations: \n1. Addition \n2. Subtraction \n3: Multiplication \n4. Division\n^ Operation 'ID' please enter the id of your choice\n"))
num1 = int(input("Enter your first number: "))
num2 = int(input("Enter your second number: "))
if choice == 1: #Addition
    num1
    num2
    ans = num1 + num2
    print("Your answer is " + str(ans))
elif choice == 2: #Subtraction
    num1
    num2
    ans = num1 - num2
    print("Your answer is " + str(ans))
elif choice == 3: #Miltiplication
    num1
    num2
    ans = num1 * num2
    print("Your answer is " + str(ans))
elif choice == 4: #Division
    num1
    num2
    ans = float(num1) / float(num2)
    print("Your answer is " + str(ans))

我也知道编写计算器应用程序的其他方法，但我正计划扩展其功能，因此我需要在三星chromebook sir 3上使用xfce 14.04的“def”，如果有必要的话。
if choice==“1”：
trythis@vks+1谢谢你，但现在我有另一个问题，它提示我输入无效，而不是告诉我答案。你的代码有很多问题。我建议你去。不，对不起，但事实并非如此help@VingeshKalal，我已经得到了最接近的答案，但它只是提示无效的输入，答案应该在哪里。@AtPython，它说的是什么输入that@VingeshKalai这不是meI我不是在问你我是在问谁说了这段代码提示我列出了错误：不支持的操作数类型和多个语法错误除法和减法的定义？虽然我看不出有任何错误syntax@AtPython是的，您的代码中似乎有更多问题，请查看最新更新。