Python-检查列是否包含列表中的值，返回值

我有一个df：

d = {'id': [1,2,3,4,5,6,7,8,9,10],
      'text': ['bill did this', 'jim did something', 'phil', 'bill did nothing',
               'carl was here', 'this is random', 'other name',
               'other bill', 'bill and carl', 'last one']}
df = pd.DataFrame(data=d)

我想检查列是否包含列表中的值，其中列表为：

list = ['bill','carl']

那么我想退回这样的东西

id  text                    contains
1   bill did this           bill
2   jim did something       
3   phil                
4   bill did nothing        bill
5   carl was here           carl
6   this is random
7   other name
8   other bill              bill
9   bill and carl           bill
9   bill and carl           carl
10  last one

尽管在同一行中处理两个或多个名称的方式可能会改变。

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有什么建议吗？

您可以创建lambda函数来检查列表中的每个项目：

d = {'id': [1,2,3,4,5,6,7,8,9,10],
      'text': ['bill did this', 'jim did something', 'phil', 'bill did nothing',
               'carl was here', 'this is random', 'other name',
               'other bill', 'bill and carl', 'last one']}
df = pd.DataFrame(data=d)

l = ['bill','carl']

df['contains'] = df['text'].apply(lambda x: ','.join([i for i in l if i in x]))

如果需要列表，可以删除join，否则它只会连接由逗号分隔的值

输出

>>df['contains']

0         bill
1             
2             
3         bill
4         carl
5             
6             
7         bill
8    bill,carl
9             
Name: contains, dtype: object

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如果比尔和卡尔都有，你怎么决定<代码>可以更改：这到底意味着什么？